Metamath Proof Explorer


Theorem idlsrgmulrcl

Description: Ideals of a ring R are closed under multiplication. (Contributed by Thierry Arnoux, 1-Jun-2024)

Ref Expression
Hypotheses idlsrgmulrval.1 ⊢ S = IDLsrg ⁡ R
idlsrgmulrval.2 ⊢ B = LIdeal ⁡ R
idlsrgmulrval.3 ⊢ ⊗ ˙ = ⋅ S
idlsrgmulrcl.1 ⊢ φ → R ∈ Ring
idlsrgmulrcl.2 ⊢ φ → I ∈ B
idlsrgmulrcl.3 ⊢ φ → J ∈ B
Assertion idlsrgmulrcl ⊢ φ → I ⊗ ˙ J ∈ B

Proof

Step Hyp Ref Expression
1 idlsrgmulrval.1 ⊢ S = IDLsrg ⁡ R
2 idlsrgmulrval.2 ⊢ B = LIdeal ⁡ R
3 idlsrgmulrval.3 ⊢ ⊗ ˙ = ⋅ S
4 idlsrgmulrcl.1 ⊢ φ → R ∈ Ring
5 idlsrgmulrcl.2 ⊢ φ → I ∈ B
6 idlsrgmulrcl.3 ⊢ φ → J ∈ B
7 eqid ⊢ mulGrp R = mulGrp R
8 eqid ⊢ LSSum ⁡ mulGrp R = LSSum ⁡ mulGrp R
9 1 2 3 7 8 4 5 6 idlsrgmulrval ⊢ φ → I ⊗ ˙ J = RSpan ⁡ R ⁡ I LSSum ⁡ mulGrp R J
10 eqid ⊢ Base R = Base R
11 10 2 lidlss ⊢ I ∈ B → I ⊆ Base R
12 5 11 syl ⊢ φ → I ⊆ Base R
13 10 2 lidlss ⊢ J ∈ B → J ⊆ Base R
14 6 13 syl ⊢ φ → J ⊆ Base R
15 10 7 8 4 12 14 ringlsmss ⊢ φ → I LSSum ⁡ mulGrp R J ⊆ Base R
16 eqid ⊢ RSpan ⁡ R = RSpan ⁡ R
17 16 10 2 rspcl ⊢ R ∈ Ring ∧ I LSSum ⁡ mulGrp R J ⊆ Base R → RSpan ⁡ R ⁡ I LSSum ⁡ mulGrp R J ∈ B
18 4 15 17 syl2anc ⊢ φ → RSpan ⁡ R ⁡ I LSSum ⁡ mulGrp R J ∈ B
19 9 18 eqeltrd ⊢ φ → I ⊗ ˙ J ∈ B