Metamath Proof Explorer


Theorem int-sqdefd

Description: SquareDefinition generator rule. (Contributed by Stanislas Polu, 7-Apr-2020)

Ref Expression
Hypotheses int-sqdefd.1 ⊢ φ → B ∈ ℝ
int-sqdefd.2 ⊢ φ → A = B
Assertion int-sqdefd ⊢ φ → A ⁢ B = A 2

Proof

Step Hyp Ref Expression
1 int-sqdefd.1 ⊢ φ → B ∈ ℝ
2 int-sqdefd.2 ⊢ φ → A = B
3 2 oveq1d ⊢ φ → A 2 = B 2
4 1 recnd ⊢ φ → B ∈ ℂ
5 4 sqvald ⊢ φ → B 2 = B ⁢ B
6 eqcom ⊢ A = B ↔ B = A
7 6 imbi2i ⊢ φ → A = B ↔ φ → B = A
8 2 7 mpbi ⊢ φ → B = A
9 8 oveq1d ⊢ φ → B ⁢ B = A ⁢ B
10 5 9 eqtrd ⊢ φ → B 2 = A ⁢ B
11 3 10 eqtrd ⊢ φ → A 2 = A ⁢ B
12 11 eqcomd ⊢ φ → A ⁢ B = A 2