Metamath Proof Explorer


Theorem isdomn2

Description: A ring is a domain iff all nonzero elements are regular elements. (Contributed by Mario Carneiro, 28-Mar-2015) (Proof shortened by SN, 21-Jun-2025)

Ref Expression
Hypotheses isdomn2.b ⊢ B = Base R
isdomn2.t ⊢ E = RLReg ⁡ R
isdomn2.z ⊢ 0 ˙ = 0 R
Assertion isdomn2 ⊢ R ∈ Domn ↔ R ∈ NzRing ∧ B ∖ 0 ˙ ⊆ E

Proof

Step Hyp Ref Expression
1 isdomn2.b ⊢ B = Base R
2 isdomn2.t ⊢ E = RLReg ⁡ R
3 isdomn2.z ⊢ 0 ˙ = 0 R
4 eqid ⊢ ⋅ R = ⋅ R
5 1 4 3 isdomn ⊢ R ∈ Domn ↔ R ∈ NzRing ∧ ∀ x ∈ B ∀ y ∈ B x ⋅ R y = 0 ˙ → x = 0 ˙ ∨ y = 0 ˙
6 eldifi ⊢ x ∈ B ∖ 0 ˙ → x ∈ B
7 2 1 4 3 isrrg ⊢ x ∈ E ↔ x ∈ B ∧ ∀ y ∈ B x ⋅ R y = 0 ˙ → y = 0 ˙
8 7 baib ⊢ x ∈ B → x ∈ E ↔ ∀ y ∈ B x ⋅ R y = 0 ˙ → y = 0 ˙
9 6 8 syl ⊢ x ∈ B ∖ 0 ˙ → x ∈ E ↔ ∀ y ∈ B x ⋅ R y = 0 ˙ → y = 0 ˙
10 9 ralbiia ⊢ ∀ x ∈ B ∖ 0 ˙ x ∈ E ↔ ∀ x ∈ B ∖ 0 ˙ ∀ y ∈ B x ⋅ R y = 0 ˙ → y = 0 ˙
11 dfss3 ⊢ B ∖ 0 ˙ ⊆ E ↔ ∀ x ∈ B ∖ 0 ˙ x ∈ E
12 isdomn5 ⊢ ∀ x ∈ B ∀ y ∈ B x ⋅ R y = 0 ˙ → x = 0 ˙ ∨ y = 0 ˙ ↔ ∀ x ∈ B ∖ 0 ˙ ∀ y ∈ B x ⋅ R y = 0 ˙ → y = 0 ˙
13 10 11 12 3bitr4ri ⊢ ∀ x ∈ B ∀ y ∈ B x ⋅ R y = 0 ˙ → x = 0 ˙ ∨ y = 0 ˙ ↔ B ∖ 0 ˙ ⊆ E
14 13 anbi2i ⊢ R ∈ NzRing ∧ ∀ x ∈ B ∀ y ∈ B x ⋅ R y = 0 ˙ → x = 0 ˙ ∨ y = 0 ˙ ↔ R ∈ NzRing ∧ B ∖ 0 ˙ ⊆ E
15 5 14 bitri ⊢ R ∈ Domn ↔ R ∈ NzRing ∧ B ∖ 0 ˙ ⊆ E