Metamath Proof Explorer


Theorem domnrrg

Description: In a domain, a nonzero element is a regular element. (Contributed by Mario Carneiro, 28-Mar-2015)

Ref Expression
Hypotheses isdomn2.b ⊢ B = Base R
isdomn2.t ⊢ E = RLReg ⁡ R
isdomn2.z ⊢ 0 ˙ = 0 R
Assertion domnrrg ⊢ R ∈ Domn ∧ X ∈ B ∧ X ≠ 0 ˙ → X ∈ E

Proof

Step Hyp Ref Expression
1 isdomn2.b ⊢ B = Base R
2 isdomn2.t ⊢ E = RLReg ⁡ R
3 isdomn2.z ⊢ 0 ˙ = 0 R
4 1 2 3 isdomn2 ⊢ R ∈ Domn ↔ R ∈ NzRing ∧ B ∖ 0 ˙ ⊆ E
5 4 simprbi ⊢ R ∈ Domn → B ∖ 0 ˙ ⊆ E
6 5 3ad2ant1 ⊢ R ∈ Domn ∧ X ∈ B ∧ X ≠ 0 ˙ → B ∖ 0 ˙ ⊆ E
7 simp2 ⊢ R ∈ Domn ∧ X ∈ B ∧ X ≠ 0 ˙ → X ∈ B
8 simp3 ⊢ R ∈ Domn ∧ X ∈ B ∧ X ≠ 0 ˙ → X ≠ 0 ˙
9 eldifsn ⊢ X ∈ B ∖ 0 ˙ ↔ X ∈ B ∧ X ≠ 0 ˙
10 7 8 9 sylanbrc ⊢ R ∈ Domn ∧ X ∈ B ∧ X ≠ 0 ˙ → X ∈ B ∖ 0 ˙
11 6 10 sseldd ⊢ R ∈ Domn ∧ X ∈ B ∧ X ≠ 0 ˙ → X ∈ E