Metamath Proof Explorer


Theorem isgrpde

Description: Deduce a group from its properties. In this version of isgrpd , we don't assume there is an expression for the inverse of x . (Contributed by Jeff Madsen, 1-Dec-2009) (Revised by NM, 6-Jan-2015)

Ref Expression
Hypotheses isgrpd.b ⊢ φ → B = Base G
isgrpd.p ⊢ φ → + ˙ = + G
isgrpd.c ⊢ φ ∧ x ∈ B ∧ y ∈ B → x + ˙ y ∈ B
isgrpd.a ⊢ φ ∧ x ∈ B ∧ y ∈ B ∧ z ∈ B → x + ˙ y + ˙ z = x + ˙ y + ˙ z
isgrpd.z ⊢ φ → 0 ˙ ∈ B
isgrpd.i ⊢ φ ∧ x ∈ B → 0 ˙ + ˙ x = x
isgrpde.n ⊢ φ ∧ x ∈ B → ∃ y ∈ B y + ˙ x = 0 ˙
Assertion isgrpde ⊢ φ → G ∈ Grp

Proof

Step Hyp Ref Expression
1 isgrpd.b ⊢ φ → B = Base G
2 isgrpd.p ⊢ φ → + ˙ = + G
3 isgrpd.c ⊢ φ ∧ x ∈ B ∧ y ∈ B → x + ˙ y ∈ B
4 isgrpd.a ⊢ φ ∧ x ∈ B ∧ y ∈ B ∧ z ∈ B → x + ˙ y + ˙ z = x + ˙ y + ˙ z
5 isgrpd.z ⊢ φ → 0 ˙ ∈ B
6 isgrpd.i ⊢ φ ∧ x ∈ B → 0 ˙ + ˙ x = x
7 isgrpde.n ⊢ φ ∧ x ∈ B → ∃ y ∈ B y + ˙ x = 0 ˙
8 3 5 6 4 7 grprida ⊢ φ ∧ x ∈ B → x + ˙ 0 ˙ = x
9 1 2 5 6 8 grpidd ⊢ φ → 0 ˙ = 0 G
10 1 2 3 4 5 6 8 ismndd ⊢ φ → G ∈ Mnd
11 1 2 9 10 7 isgrpd2e ⊢ φ → G ∈ Grp