Metamath Proof Explorer


Theorem ismbl

Description: The predicate " A is Lebesgue-measurable". A set is measurable if it splits every other set x in a "nice" way, that is, if the measure of the pieces x i^i A and x \ A sum up to the measure of x (assuming that the measure of x is a real number, so that this addition makes sense). (Contributed by Mario Carneiro, 17-Mar-2014)

Ref Expression
Assertion ismbl ⊢ A ∈ dom ⁡ vol ↔ A ⊆ ℝ ∧ ∀ x ∈ 𝒫 ℝ vol * ⁡ x ∈ ℝ → vol * ⁡ x = vol * ⁡ x ∩ A + vol * ⁡ x ∖ A

Proof

Step Hyp Ref Expression
1 ineq2 ⊢ y = A → x ∩ y = x ∩ A
2 1 fveq2d ⊢ y = A → vol * ⁡ x ∩ y = vol * ⁡ x ∩ A
3 difeq2 ⊢ y = A → x ∖ y = x ∖ A
4 3 fveq2d ⊢ y = A → vol * ⁡ x ∖ y = vol * ⁡ x ∖ A
5 2 4 oveq12d ⊢ y = A → vol * ⁡ x ∩ y + vol * ⁡ x ∖ y = vol * ⁡ x ∩ A + vol * ⁡ x ∖ A
6 5 eqeq2d ⊢ y = A → vol * ⁡ x = vol * ⁡ x ∩ y + vol * ⁡ x ∖ y ↔ vol * ⁡ x = vol * ⁡ x ∩ A + vol * ⁡ x ∖ A
7 6 ralbidv ⊢ y = A → ∀ x ∈ vol * -1 ℝ vol * ⁡ x = vol * ⁡ x ∩ y + vol * ⁡ x ∖ y ↔ ∀ x ∈ vol * -1 ℝ vol * ⁡ x = vol * ⁡ x ∩ A + vol * ⁡ x ∖ A
8 df-vol ⊢ vol = vol * ↾ y | ∀ x ∈ vol * -1 ℝ vol * ⁡ x = vol * ⁡ x ∩ y + vol * ⁡ x ∖ y
9 8 dmeqi ⊢ dom ⁡ vol = dom ⁡ vol * ↾ y | ∀ x ∈ vol * -1 ℝ vol * ⁡ x = vol * ⁡ x ∩ y + vol * ⁡ x ∖ y
10 dmres ⊢ dom ⁡ vol * ↾ y | ∀ x ∈ vol * -1 ℝ vol * ⁡ x = vol * ⁡ x ∩ y + vol * ⁡ x ∖ y = y | ∀ x ∈ vol * -1 ℝ vol * ⁡ x = vol * ⁡ x ∩ y + vol * ⁡ x ∖ y ∩ dom ⁡ vol *
11 ovolf ⊢ vol * : 𝒫 ℝ ⟶ 0 +∞
12 11 fdmi ⊢ dom ⁡ vol * = 𝒫 ℝ
13 12 ineq2i ⊢ y | ∀ x ∈ vol * -1 ℝ vol * ⁡ x = vol * ⁡ x ∩ y + vol * ⁡ x ∖ y ∩ dom ⁡ vol * = y | ∀ x ∈ vol * -1 ℝ vol * ⁡ x = vol * ⁡ x ∩ y + vol * ⁡ x ∖ y ∩ 𝒫 ℝ
14 9 10 13 3eqtri ⊢ dom ⁡ vol = y | ∀ x ∈ vol * -1 ℝ vol * ⁡ x = vol * ⁡ x ∩ y + vol * ⁡ x ∖ y ∩ 𝒫 ℝ
15 dfrab2 ⊢ y ∈ 𝒫 ℝ | ∀ x ∈ vol * -1 ℝ vol * ⁡ x = vol * ⁡ x ∩ y + vol * ⁡ x ∖ y = y | ∀ x ∈ vol * -1 ℝ vol * ⁡ x = vol * ⁡ x ∩ y + vol * ⁡ x ∖ y ∩ 𝒫 ℝ
16 14 15 eqtr4i ⊢ dom ⁡ vol = y ∈ 𝒫 ℝ | ∀ x ∈ vol * -1 ℝ vol * ⁡ x = vol * ⁡ x ∩ y + vol * ⁡ x ∖ y
17 7 16 elrab2 ⊢ A ∈ dom ⁡ vol ↔ A ∈ 𝒫 ℝ ∧ ∀ x ∈ vol * -1 ℝ vol * ⁡ x = vol * ⁡ x ∩ A + vol * ⁡ x ∖ A
18 reex ⊢ ℝ ∈ V
19 18 elpw2 ⊢ A ∈ 𝒫 ℝ ↔ A ⊆ ℝ
20 ffn ⊢ vol * : 𝒫 ℝ ⟶ 0 +∞ → vol * Fn 𝒫 ℝ
21 elpreima ⊢ vol * Fn 𝒫 ℝ → x ∈ vol * -1 ℝ ↔ x ∈ 𝒫 ℝ ∧ vol * ⁡ x ∈ ℝ
22 11 20 21 mp2b ⊢ x ∈ vol * -1 ℝ ↔ x ∈ 𝒫 ℝ ∧ vol * ⁡ x ∈ ℝ
23 22 imbi1i ⊢ x ∈ vol * -1 ℝ → vol * ⁡ x = vol * ⁡ x ∩ A + vol * ⁡ x ∖ A ↔ x ∈ 𝒫 ℝ ∧ vol * ⁡ x ∈ ℝ → vol * ⁡ x = vol * ⁡ x ∩ A + vol * ⁡ x ∖ A
24 impexp ⊢ x ∈ 𝒫 ℝ ∧ vol * ⁡ x ∈ ℝ → vol * ⁡ x = vol * ⁡ x ∩ A + vol * ⁡ x ∖ A ↔ x ∈ 𝒫 ℝ → vol * ⁡ x ∈ ℝ → vol * ⁡ x = vol * ⁡ x ∩ A + vol * ⁡ x ∖ A
25 23 24 bitri ⊢ x ∈ vol * -1 ℝ → vol * ⁡ x = vol * ⁡ x ∩ A + vol * ⁡ x ∖ A ↔ x ∈ 𝒫 ℝ → vol * ⁡ x ∈ ℝ → vol * ⁡ x = vol * ⁡ x ∩ A + vol * ⁡ x ∖ A
26 25 ralbii2 ⊢ ∀ x ∈ vol * -1 ℝ vol * ⁡ x = vol * ⁡ x ∩ A + vol * ⁡ x ∖ A ↔ ∀ x ∈ 𝒫 ℝ vol * ⁡ x ∈ ℝ → vol * ⁡ x = vol * ⁡ x ∩ A + vol * ⁡ x ∖ A
27 19 26 anbi12i ⊢ A ∈ 𝒫 ℝ ∧ ∀ x ∈ vol * -1 ℝ vol * ⁡ x = vol * ⁡ x ∩ A + vol * ⁡ x ∖ A ↔ A ⊆ ℝ ∧ ∀ x ∈ 𝒫 ℝ vol * ⁡ x ∈ ℝ → vol * ⁡ x = vol * ⁡ x ∩ A + vol * ⁡ x ∖ A
28 17 27 bitri ⊢ A ∈ dom ⁡ vol ↔ A ⊆ ℝ ∧ ∀ x ∈ 𝒫 ℝ vol * ⁡ x ∈ ℝ → vol * ⁡ x = vol * ⁡ x ∩ A + vol * ⁡ x ∖ A