Metamath Proof Explorer


Theorem itcovalt2lem1

Description: Lemma 1 for itcovalt2 : induction basis. (Contributed by AV, 5-May-2024)

Ref Expression
Hypothesis itcovalt2.f ⊢ F = n ∈ ℕ 0 ⟼ 2 ⁢ n + C
Assertion itcovalt2lem1 ⊢ C ∈ ℕ 0 → IterComp ⁡ F ⁡ 0 = n ∈ ℕ 0 ⟼ n + C ⁢ 2 0 − C

Proof

Step Hyp Ref Expression
1 itcovalt2.f ⊢ F = n ∈ ℕ 0 ⟼ 2 ⁢ n + C
2 nn0ex ⊢ ℕ 0 ∈ V
3 ovexd ⊢ n ∈ ℕ 0 → 2 ⁢ n + C ∈ V
4 3 rgen ⊢ ∀ n ∈ ℕ 0 2 ⁢ n + C ∈ V
5 2 4 pm3.2i ⊢ ℕ 0 ∈ V ∧ ∀ n ∈ ℕ 0 2 ⁢ n + C ∈ V
6 1 itcoval0mpt ⊢ ℕ 0 ∈ V ∧ ∀ n ∈ ℕ 0 2 ⁢ n + C ∈ V → IterComp ⁡ F ⁡ 0 = n ∈ ℕ 0 ⟼ n
7 5 6 mp1i ⊢ C ∈ ℕ 0 → IterComp ⁡ F ⁡ 0 = n ∈ ℕ 0 ⟼ n
8 simpr ⊢ C ∈ ℕ 0 ∧ n ∈ ℕ 0 → n ∈ ℕ 0
9 8 nn0cnd ⊢ C ∈ ℕ 0 ∧ n ∈ ℕ 0 → n ∈ ℂ
10 simpl ⊢ C ∈ ℕ 0 ∧ n ∈ ℕ 0 → C ∈ ℕ 0
11 10 nn0cnd ⊢ C ∈ ℕ 0 ∧ n ∈ ℕ 0 → C ∈ ℂ
12 2nn0 ⊢ 2 ∈ ℕ 0
13 12 numexp0 ⊢ 2 0 = 1
14 13 a1i ⊢ C ∈ ℕ 0 ∧ n ∈ ℕ 0 → 2 0 = 1
15 14 oveq2d ⊢ C ∈ ℕ 0 ∧ n ∈ ℕ 0 → n + C ⁢ 2 0 = n + C ⋅ 1
16 8 10 nn0addcld ⊢ C ∈ ℕ 0 ∧ n ∈ ℕ 0 → n + C ∈ ℕ 0
17 16 nn0cnd ⊢ C ∈ ℕ 0 ∧ n ∈ ℕ 0 → n + C ∈ ℂ
18 17 mulridd ⊢ C ∈ ℕ 0 ∧ n ∈ ℕ 0 → n + C ⋅ 1 = n + C
19 15 18 eqtrd ⊢ C ∈ ℕ 0 ∧ n ∈ ℕ 0 → n + C ⁢ 2 0 = n + C
20 9 11 19 mvrraddd ⊢ C ∈ ℕ 0 ∧ n ∈ ℕ 0 → n + C ⁢ 2 0 − C = n
21 20 eqcomd ⊢ C ∈ ℕ 0 ∧ n ∈ ℕ 0 → n = n + C ⁢ 2 0 − C
22 21 mpteq2dva ⊢ C ∈ ℕ 0 → n ∈ ℕ 0 ⟼ n = n ∈ ℕ 0 ⟼ n + C ⁢ 2 0 − C
23 7 22 eqtrd ⊢ C ∈ ℕ 0 → IterComp ⁡ F ⁡ 0 = n ∈ ℕ 0 ⟼ n + C ⁢ 2 0 − C