Metamath Proof Explorer


Theorem kur14lem1

Description: Lemma for kur14 . (Contributed by Mario Carneiro, 17-Feb-2015)

Ref Expression
Hypotheses kur14lem1.a ⊢ A ⊆ X
kur14lem1.c ⊢ X ∖ A ∈ T
kur14lem1.k ⊢ K ⁡ A ∈ T
Assertion kur14lem1 ⊢ N = A → N ⊆ X ∧ X ∖ N K ⁡ N ⊆ T

Proof

Step Hyp Ref Expression
1 kur14lem1.a ⊢ A ⊆ X
2 kur14lem1.c ⊢ X ∖ A ∈ T
3 kur14lem1.k ⊢ K ⁡ A ∈ T
4 sseq1 ⊢ N = A → N ⊆ X ↔ A ⊆ X
5 1 4 mpbiri ⊢ N = A → N ⊆ X
6 difeq2 ⊢ N = A → X ∖ N = X ∖ A
7 fveq2 ⊢ N = A → K ⁡ N = K ⁡ A
8 6 7 preq12d ⊢ N = A → X ∖ N K ⁡ N = X ∖ A K ⁡ A
9 prssi ⊢ X ∖ A ∈ T ∧ K ⁡ A ∈ T → X ∖ A K ⁡ A ⊆ T
10 2 3 9 mp2an ⊢ X ∖ A K ⁡ A ⊆ T
11 8 10 eqsstrdi ⊢ N = A → X ∖ N K ⁡ N ⊆ T
12 5 11 jca ⊢ N = A → N ⊆ X ∧ X ∖ N K ⁡ N ⊆ T