Metamath Proof Explorer


Theorem lcfrlem14

Description: Lemma for lcfr . (Contributed by NM, 10-Mar-2015)

Ref Expression
Hypotheses lcf1o.h ⊢ H = LHyp ⁡ K
lcf1o.o ⊢ ⊥ ˙ = ocH ⁡ K ⁡ W
lcf1o.u ⊢ U = DVecH ⁡ K ⁡ W
lcf1o.v ⊢ V = Base U
lcf1o.a ⊢ + ˙ = + U
lcf1o.t ⊢ · ˙ = ⋅ U
lcf1o.s ⊢ S = Scalar ⁡ U
lcf1o.r ⊢ R = Base S
lcf1o.z ⊢ 0 ˙ = 0 U
lcf1o.f ⊢ F = LFnl ⁡ U
lcf1o.l ⊢ L = LKer ⁡ U
lcf1o.d ⊢ D = LDual ⁡ U
lcf1o.q ⊢ Q = 0 D
lcf1o.c ⊢ C = f ∈ F | ⊥ ˙ ⁡ ⊥ ˙ ⁡ L ⁡ f = L ⁡ f
lcf1o.j ⊢ J = x ∈ V ∖ 0 ˙ ⟼ v ∈ V ⟼ ι k ∈ R | ∃ w ∈ ⊥ ˙ ⁡ x v = w + ˙ k · ˙ x
lcflo.k ⊢ φ → K ∈ HL ∧ W ∈ H
lcfrlem10.x ⊢ φ → X ∈ V ∖ 0 ˙
lcfrlem14.n ⊢ N = LSpan ⁡ U
Assertion lcfrlem14 ⊢ φ → ⊥ ˙ ⁡ L ⁡ J ⁡ X = N ⁡ X

Proof

Step Hyp Ref Expression
1 lcf1o.h ⊢ H = LHyp ⁡ K
2 lcf1o.o ⊢ ⊥ ˙ = ocH ⁡ K ⁡ W
3 lcf1o.u ⊢ U = DVecH ⁡ K ⁡ W
4 lcf1o.v ⊢ V = Base U
5 lcf1o.a ⊢ + ˙ = + U
6 lcf1o.t ⊢ · ˙ = ⋅ U
7 lcf1o.s ⊢ S = Scalar ⁡ U
8 lcf1o.r ⊢ R = Base S
9 lcf1o.z ⊢ 0 ˙ = 0 U
10 lcf1o.f ⊢ F = LFnl ⁡ U
11 lcf1o.l ⊢ L = LKer ⁡ U
12 lcf1o.d ⊢ D = LDual ⁡ U
13 lcf1o.q ⊢ Q = 0 D
14 lcf1o.c ⊢ C = f ∈ F | ⊥ ˙ ⁡ ⊥ ˙ ⁡ L ⁡ f = L ⁡ f
15 lcf1o.j ⊢ J = x ∈ V ∖ 0 ˙ ⟼ v ∈ V ⟼ ι k ∈ R | ∃ w ∈ ⊥ ˙ ⁡ x v = w + ˙ k · ˙ x
16 lcflo.k ⊢ φ → K ∈ HL ∧ W ∈ H
17 lcfrlem10.x ⊢ φ → X ∈ V ∖ 0 ˙
18 lcfrlem14.n ⊢ N = LSpan ⁡ U
19 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 lcfrlem11 ⊢ φ → L ⁡ J ⁡ X = ⊥ ˙ ⁡ X
20 17 eldifad ⊢ φ → X ∈ V
21 20 snssd ⊢ φ → X ⊆ V
22 1 3 2 4 18 16 21 dochocsp ⊢ φ → ⊥ ˙ ⁡ N ⁡ X = ⊥ ˙ ⁡ X
23 19 22 eqtr4d ⊢ φ → L ⁡ J ⁡ X = ⊥ ˙ ⁡ N ⁡ X
24 23 fveq2d ⊢ φ → ⊥ ˙ ⁡ L ⁡ J ⁡ X = ⊥ ˙ ⁡ ⊥ ˙ ⁡ N ⁡ X
25 eqid ⊢ DIsoH ⁡ K ⁡ W = DIsoH ⁡ K ⁡ W
26 1 3 4 18 25 dihlsprn ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ V → N ⁡ X ∈ ran ⁡ DIsoH ⁡ K ⁡ W
27 16 20 26 syl2anc ⊢ φ → N ⁡ X ∈ ran ⁡ DIsoH ⁡ K ⁡ W
28 1 25 2 dochoc ⊢ K ∈ HL ∧ W ∈ H ∧ N ⁡ X ∈ ran ⁡ DIsoH ⁡ K ⁡ W → ⊥ ˙ ⁡ ⊥ ˙ ⁡ N ⁡ X = N ⁡ X
29 16 27 28 syl2anc ⊢ φ → ⊥ ˙ ⁡ ⊥ ˙ ⁡ N ⁡ X = N ⁡ X
30 24 29 eqtrd ⊢ φ → ⊥ ˙ ⁡ L ⁡ J ⁡ X = N ⁡ X