Metamath Proof Explorer


Theorem lclkrlem2k

Description: Lemma for lclkr . Kernel closure when X is zero. (Contributed by NM, 18-Jan-2015)

Ref Expression
Hypotheses lclkrlem2f.h ⊢ H = LHyp ⁡ K
lclkrlem2f.o ⊢ ⊥ ˙ = ocH ⁡ K ⁡ W
lclkrlem2f.u ⊢ U = DVecH ⁡ K ⁡ W
lclkrlem2f.v ⊢ V = Base U
lclkrlem2f.s ⊢ S = Scalar ⁡ U
lclkrlem2f.q ⊢ Q = 0 S
lclkrlem2f.z ⊢ 0 ˙ = 0 U
lclkrlem2f.a ⊢ ⊕ ˙ = LSSum ⁡ U
lclkrlem2f.n ⊢ N = LSpan ⁡ U
lclkrlem2f.f ⊢ F = LFnl ⁡ U
lclkrlem2f.j ⊢ J = LSHyp ⁡ U
lclkrlem2f.l ⊢ L = LKer ⁡ U
lclkrlem2f.d ⊢ D = LDual ⁡ U
lclkrlem2f.p ⊢ + ˙ = + D
lclkrlem2f.k ⊢ φ → K ∈ HL ∧ W ∈ H
lclkrlem2f.b ⊢ φ → B ∈ V ∖ 0 ˙
lclkrlem2f.e ⊢ φ → E ∈ F
lclkrlem2f.g ⊢ φ → G ∈ F
lclkrlem2f.le ⊢ φ → L ⁡ E = ⊥ ˙ ⁡ X
lclkrlem2f.lg ⊢ φ → L ⁡ G = ⊥ ˙ ⁡ Y
lclkrlem2f.kb ⊢ φ → E + ˙ G ⁡ B = Q
lclkrlem2f.nx ⊢ φ → ¬ X ∈ ⊥ ˙ ⁡ B ∨ ¬ Y ∈ ⊥ ˙ ⁡ B
lclkrlem2k.x ⊢ φ → X = 0 ˙
lclkrlem2k.y ⊢ φ → Y ∈ V
Assertion lclkrlem2k ⊢ φ → ⊥ ˙ ⁡ ⊥ ˙ ⁡ L ⁡ E + ˙ G = L ⁡ E + ˙ G

Proof

Step Hyp Ref Expression
1 lclkrlem2f.h ⊢ H = LHyp ⁡ K
2 lclkrlem2f.o ⊢ ⊥ ˙ = ocH ⁡ K ⁡ W
3 lclkrlem2f.u ⊢ U = DVecH ⁡ K ⁡ W
4 lclkrlem2f.v ⊢ V = Base U
5 lclkrlem2f.s ⊢ S = Scalar ⁡ U
6 lclkrlem2f.q ⊢ Q = 0 S
7 lclkrlem2f.z ⊢ 0 ˙ = 0 U
8 lclkrlem2f.a ⊢ ⊕ ˙ = LSSum ⁡ U
9 lclkrlem2f.n ⊢ N = LSpan ⁡ U
10 lclkrlem2f.f ⊢ F = LFnl ⁡ U
11 lclkrlem2f.j ⊢ J = LSHyp ⁡ U
12 lclkrlem2f.l ⊢ L = LKer ⁡ U
13 lclkrlem2f.d ⊢ D = LDual ⁡ U
14 lclkrlem2f.p ⊢ + ˙ = + D
15 lclkrlem2f.k ⊢ φ → K ∈ HL ∧ W ∈ H
16 lclkrlem2f.b ⊢ φ → B ∈ V ∖ 0 ˙
17 lclkrlem2f.e ⊢ φ → E ∈ F
18 lclkrlem2f.g ⊢ φ → G ∈ F
19 lclkrlem2f.le ⊢ φ → L ⁡ E = ⊥ ˙ ⁡ X
20 lclkrlem2f.lg ⊢ φ → L ⁡ G = ⊥ ˙ ⁡ Y
21 lclkrlem2f.kb ⊢ φ → E + ˙ G ⁡ B = Q
22 lclkrlem2f.nx ⊢ φ → ¬ X ∈ ⊥ ˙ ⁡ B ∨ ¬ Y ∈ ⊥ ˙ ⁡ B
23 lclkrlem2k.x ⊢ φ → X = 0 ˙
24 lclkrlem2k.y ⊢ φ → Y ∈ V
25 1 3 15 dvhlmod ⊢ φ → U ∈ LMod
26 10 13 14 25 17 18 ldualvaddcom ⊢ φ → E + ˙ G = G + ˙ E
27 26 fveq1d ⊢ φ → E + ˙ G ⁡ B = G + ˙ E ⁡ B
28 27 21 eqtr3d ⊢ φ → G + ˙ E ⁡ B = Q
29 22 orcomd ⊢ φ → ¬ Y ∈ ⊥ ˙ ⁡ B ∨ ¬ X ∈ ⊥ ˙ ⁡ B
30 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 18 17 20 19 28 29 24 23 lclkrlem2j ⊢ φ → ⊥ ˙ ⁡ ⊥ ˙ ⁡ L ⁡ G + ˙ E = L ⁡ G + ˙ E
31 26 fveq2d ⊢ φ → L ⁡ E + ˙ G = L ⁡ G + ˙ E
32 31 fveq2d ⊢ φ → ⊥ ˙ ⁡ L ⁡ E + ˙ G = ⊥ ˙ ⁡ L ⁡ G + ˙ E
33 32 fveq2d ⊢ φ → ⊥ ˙ ⁡ ⊥ ˙ ⁡ L ⁡ E + ˙ G = ⊥ ˙ ⁡ ⊥ ˙ ⁡ L ⁡ G + ˙ E
34 30 33 31 3eqtr4d ⊢ φ → ⊥ ˙ ⁡ ⊥ ˙ ⁡ L ⁡ E + ˙ G = L ⁡ E + ˙ G