Metamath Proof Explorer


Theorem linevalexample

Description: The polynomial x - 3 over ZZ evaluated for x = 5 results in 2. (Contributed by AV, 3-Jul-2019)

Ref Expression
Hypotheses linevalexample.p ⊢ P = Poly 1 ⁡ ℤ ring
linevalexample.b ⊢ B = Base P
linevalexample.x ⊢ X = var 1 ⁡ ℤ ring
linevalexample.m ⊢ - ˙ = - P
linevalexample.a ⊢ A = algSc ⁡ P
linevalexample.g ⊢ G = X - ˙ A ⁡ 3
linevalexample.o ⊢ O = eval 1 ⁡ ℤ ring
Assertion linevalexample ⊢ O ⁡ X - ˙ A ⁡ 3 ⁡ 5 = 2

Proof

Step Hyp Ref Expression
1 linevalexample.p ⊢ P = Poly 1 ⁡ ℤ ring
2 linevalexample.b ⊢ B = Base P
3 linevalexample.x ⊢ X = var 1 ⁡ ℤ ring
4 linevalexample.m ⊢ - ˙ = - P
5 linevalexample.a ⊢ A = algSc ⁡ P
6 linevalexample.g ⊢ G = X - ˙ A ⁡ 3
7 linevalexample.o ⊢ O = eval 1 ⁡ ℤ ring
8 zringcrng ⊢ ℤ ring ∈ CRing
9 zringbas ⊢ ℤ = Base ℤ ring
10 eqid ⊢ X - ˙ A ⁡ 3 = X - ˙ A ⁡ 3
11 3z ⊢ 3 ∈ ℤ
12 11 a1i ⊢ ℤ ring ∈ CRing → 3 ∈ ℤ
13 id ⊢ ℤ ring ∈ CRing → ℤ ring ∈ CRing
14 5nn0 ⊢ 5 ∈ ℕ 0
15 14 nn0zi ⊢ 5 ∈ ℤ
16 15 a1i ⊢ ℤ ring ∈ CRing → 5 ∈ ℤ
17 1 2 9 3 4 5 10 12 7 13 16 lineval ⊢ ℤ ring ∈ CRing → O ⁡ X - ˙ A ⁡ 3 ⁡ 5 = 5 - ℤ ring 3
18 8 17 ax-mp ⊢ O ⁡ X - ˙ A ⁡ 3 ⁡ 5 = 5 - ℤ ring 3
19 eqid ⊢ - ℤ ring = - ℤ ring
20 19 zringsubgval ⊢ 5 ∈ ℤ ∧ 3 ∈ ℤ → 5 − 3 = 5 - ℤ ring 3
21 15 11 20 mp2an ⊢ 5 − 3 = 5 - ℤ ring 3
22 5cn ⊢ 5 ∈ ℂ
23 3cn ⊢ 3 ∈ ℂ
24 2cn ⊢ 2 ∈ ℂ
25 3p2e5 ⊢ 3 + 2 = 5
26 22 23 24 25 subaddrii ⊢ 5 − 3 = 2
27 18 21 26 3eqtr2i ⊢ O ⁡ X - ˙ A ⁡ 3 ⁡ 5 = 2