Metamath Proof Explorer


Theorem lsscl

Description: Closure property of a subspace. (Contributed by NM, 8-Dec-2013) (Revised by Mario Carneiro, 8-Jan-2015)

Ref Expression
Hypotheses lsscl.f ⊢ F = Scalar ⁡ W
lsscl.b ⊢ B = Base F
lsscl.p ⊢ + ˙ = + W
lsscl.t ⊢ · ˙ = ⋅ W
lsscl.s ⊢ S = LSubSp ⁡ W
Assertion lsscl ⊢ U ∈ S ∧ Z ∈ B ∧ X ∈ U ∧ Y ∈ U → Z · ˙ X + ˙ Y ∈ U

Proof

Step Hyp Ref Expression
1 lsscl.f ⊢ F = Scalar ⁡ W
2 lsscl.b ⊢ B = Base F
3 lsscl.p ⊢ + ˙ = + W
4 lsscl.t ⊢ · ˙ = ⋅ W
5 lsscl.s ⊢ S = LSubSp ⁡ W
6 eqid ⊢ Base W = Base W
7 1 2 6 3 4 5 islss ⊢ U ∈ S ↔ U ⊆ Base W ∧ U ≠ ∅ ∧ ∀ x ∈ B ∀ a ∈ U ∀ b ∈ U x · ˙ a + ˙ b ∈ U
8 7 simp3bi ⊢ U ∈ S → ∀ x ∈ B ∀ a ∈ U ∀ b ∈ U x · ˙ a + ˙ b ∈ U
9 oveq1 ⊢ x = Z → x · ˙ a = Z · ˙ a
10 9 oveq1d ⊢ x = Z → x · ˙ a + ˙ b = Z · ˙ a + ˙ b
11 10 eleq1d ⊢ x = Z → x · ˙ a + ˙ b ∈ U ↔ Z · ˙ a + ˙ b ∈ U
12 oveq2 ⊢ a = X → Z · ˙ a = Z · ˙ X
13 12 oveq1d ⊢ a = X → Z · ˙ a + ˙ b = Z · ˙ X + ˙ b
14 13 eleq1d ⊢ a = X → Z · ˙ a + ˙ b ∈ U ↔ Z · ˙ X + ˙ b ∈ U
15 oveq2 ⊢ b = Y → Z · ˙ X + ˙ b = Z · ˙ X + ˙ Y
16 15 eleq1d ⊢ b = Y → Z · ˙ X + ˙ b ∈ U ↔ Z · ˙ X + ˙ Y ∈ U
17 11 14 16 rspc3v ⊢ Z ∈ B ∧ X ∈ U ∧ Y ∈ U → ∀ x ∈ B ∀ a ∈ U ∀ b ∈ U x · ˙ a + ˙ b ∈ U → Z · ˙ X + ˙ Y ∈ U
18 8 17 mpan9 ⊢ U ∈ S ∧ Z ∈ B ∧ X ∈ U ∧ Y ∈ U → Z · ˙ X + ˙ Y ∈ U