Metamath Proof Explorer


Theorem ltrneq

Description: The equality of two translations is determined by their equality at atoms not under co-atom W . (Contributed by NM, 20-Jun-2013)

Ref Expression
Hypotheses ltrne.l ⊢ ≤ ˙ = ≤ K
ltrne.a ⊢ A = Atoms ⁡ K
ltrne.h ⊢ H = LHyp ⁡ K
ltrne.t ⊢ T = LTrn ⁡ K ⁡ W
Assertion ltrneq ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ G ∈ T → ∀ p ∈ A ¬ p ≤ ˙ W → F ⁡ p = G ⁡ p ↔ F = G

Proof

Step Hyp Ref Expression
1 ltrne.l ⊢ ≤ ˙ = ≤ K
2 ltrne.a ⊢ A = Atoms ⁡ K
3 ltrne.h ⊢ H = LHyp ⁡ K
4 ltrne.t ⊢ T = LTrn ⁡ K ⁡ W
5 simp11 ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ G ∈ T ∧ p ∈ A ∧ p ≤ ˙ W → K ∈ HL ∧ W ∈ H
6 simp12 ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ G ∈ T ∧ p ∈ A ∧ p ≤ ˙ W → F ∈ T
7 eqid ⊢ Base K = Base K
8 7 2 atbase ⊢ p ∈ A → p ∈ Base K
9 8 3ad2ant2 ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ G ∈ T ∧ p ∈ A ∧ p ≤ ˙ W → p ∈ Base K
10 simp3 ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ G ∈ T ∧ p ∈ A ∧ p ≤ ˙ W → p ≤ ˙ W
11 7 1 3 4 ltrnval1 ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ p ∈ Base K ∧ p ≤ ˙ W → F ⁡ p = p
12 5 6 9 10 11 syl112anc ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ G ∈ T ∧ p ∈ A ∧ p ≤ ˙ W → F ⁡ p = p
13 simp13 ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ G ∈ T ∧ p ∈ A ∧ p ≤ ˙ W → G ∈ T
14 7 1 3 4 ltrnval1 ⊢ K ∈ HL ∧ W ∈ H ∧ G ∈ T ∧ p ∈ Base K ∧ p ≤ ˙ W → G ⁡ p = p
15 5 13 9 10 14 syl112anc ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ G ∈ T ∧ p ∈ A ∧ p ≤ ˙ W → G ⁡ p = p
16 12 15 eqtr4d ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ G ∈ T ∧ p ∈ A ∧ p ≤ ˙ W → F ⁡ p = G ⁡ p
17 16 3expia ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ G ∈ T ∧ p ∈ A → p ≤ ˙ W → F ⁡ p = G ⁡ p
18 pm2.61 ⊢ p ≤ ˙ W → F ⁡ p = G ⁡ p → ¬ p ≤ ˙ W → F ⁡ p = G ⁡ p → F ⁡ p = G ⁡ p
19 17 18 syl ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ G ∈ T ∧ p ∈ A → ¬ p ≤ ˙ W → F ⁡ p = G ⁡ p → F ⁡ p = G ⁡ p
20 re1tbw2 ⊢ F ⁡ p = G ⁡ p → ¬ p ≤ ˙ W → F ⁡ p = G ⁡ p
21 19 20 impbid1 ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ G ∈ T ∧ p ∈ A → ¬ p ≤ ˙ W → F ⁡ p = G ⁡ p ↔ F ⁡ p = G ⁡ p
22 21 ralbidva ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ G ∈ T → ∀ p ∈ A ¬ p ≤ ˙ W → F ⁡ p = G ⁡ p ↔ ∀ p ∈ A F ⁡ p = G ⁡ p
23 2 3 4 ltrneq2 ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ G ∈ T → ∀ p ∈ A F ⁡ p = G ⁡ p ↔ F = G
24 22 23 bitrd ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ G ∈ T → ∀ p ∈ A ¬ p ≤ ˙ W → F ⁡ p = G ⁡ p ↔ F = G