Metamath Proof Explorer


Theorem mapdpglem16

Description: Lemma for mapdpg . Baer p. 45, line 7: "Likewise we see that z =/= 0." (Contributed by NM, 20-Mar-2015)

Ref Expression
Hypotheses mapdpglem.h ⊢ H = LHyp ⁡ K
mapdpglem.m ⊢ M = mapd ⁡ K ⁡ W
mapdpglem.u ⊢ U = DVecH ⁡ K ⁡ W
mapdpglem.v ⊢ V = Base U
mapdpglem.s ⊢ - ˙ = - U
mapdpglem.n ⊢ N = LSpan ⁡ U
mapdpglem.c ⊢ C = LCDual ⁡ K ⁡ W
mapdpglem.k ⊢ φ → K ∈ HL ∧ W ∈ H
mapdpglem.x ⊢ φ → X ∈ V
mapdpglem.y ⊢ φ → Y ∈ V
mapdpglem1.p ⊢ ⊕ ˙ = LSSum ⁡ C
mapdpglem2.j ⊢ J = LSpan ⁡ C
mapdpglem3.f ⊢ F = Base C
mapdpglem3.te ⊢ φ → t ∈ M ⁡ N ⁡ X ⊕ ˙ M ⁡ N ⁡ Y
mapdpglem3.a ⊢ A = Scalar ⁡ U
mapdpglem3.b ⊢ B = Base A
mapdpglem3.t ⊢ · ˙ = ⋅ C
mapdpglem3.r ⊢ R = - C
mapdpglem3.g ⊢ φ → G ∈ F
mapdpglem3.e ⊢ φ → M ⁡ N ⁡ X = J ⁡ G
mapdpglem4.q ⊢ Q = 0 U
mapdpglem.ne ⊢ φ → N ⁡ X ≠ N ⁡ Y
mapdpglem4.jt ⊢ φ → M ⁡ N ⁡ X - ˙ Y = J ⁡ t
mapdpglem4.z ⊢ 0 ˙ = 0 A
mapdpglem4.g4 ⊢ φ → g ∈ B
mapdpglem4.z4 ⊢ φ → z ∈ M ⁡ N ⁡ Y
mapdpglem4.t4 ⊢ φ → t = g · ˙ G R z
mapdpglem4.xn ⊢ φ → X ≠ Q
mapdpglem12.yn ⊢ φ → Y ≠ Q
Assertion mapdpglem16 ⊢ φ → z ≠ 0 C

Proof

Step Hyp Ref Expression
1 mapdpglem.h ⊢ H = LHyp ⁡ K
2 mapdpglem.m ⊢ M = mapd ⁡ K ⁡ W
3 mapdpglem.u ⊢ U = DVecH ⁡ K ⁡ W
4 mapdpglem.v ⊢ V = Base U
5 mapdpglem.s ⊢ - ˙ = - U
6 mapdpglem.n ⊢ N = LSpan ⁡ U
7 mapdpglem.c ⊢ C = LCDual ⁡ K ⁡ W
8 mapdpglem.k ⊢ φ → K ∈ HL ∧ W ∈ H
9 mapdpglem.x ⊢ φ → X ∈ V
10 mapdpglem.y ⊢ φ → Y ∈ V
11 mapdpglem1.p ⊢ ⊕ ˙ = LSSum ⁡ C
12 mapdpglem2.j ⊢ J = LSpan ⁡ C
13 mapdpglem3.f ⊢ F = Base C
14 mapdpglem3.te ⊢ φ → t ∈ M ⁡ N ⁡ X ⊕ ˙ M ⁡ N ⁡ Y
15 mapdpglem3.a ⊢ A = Scalar ⁡ U
16 mapdpglem3.b ⊢ B = Base A
17 mapdpglem3.t ⊢ · ˙ = ⋅ C
18 mapdpglem3.r ⊢ R = - C
19 mapdpglem3.g ⊢ φ → G ∈ F
20 mapdpglem3.e ⊢ φ → M ⁡ N ⁡ X = J ⁡ G
21 mapdpglem4.q ⊢ Q = 0 U
22 mapdpglem.ne ⊢ φ → N ⁡ X ≠ N ⁡ Y
23 mapdpglem4.jt ⊢ φ → M ⁡ N ⁡ X - ˙ Y = J ⁡ t
24 mapdpglem4.z ⊢ 0 ˙ = 0 A
25 mapdpglem4.g4 ⊢ φ → g ∈ B
26 mapdpglem4.z4 ⊢ φ → z ∈ M ⁡ N ⁡ Y
27 mapdpglem4.t4 ⊢ φ → t = g · ˙ G R z
28 mapdpglem4.xn ⊢ φ → X ≠ Q
29 mapdpglem12.yn ⊢ φ → Y ≠ Q
30 8 adantr ⊢ φ ∧ z = 0 C → K ∈ HL ∧ W ∈ H
31 9 adantr ⊢ φ ∧ z = 0 C → X ∈ V
32 10 adantr ⊢ φ ∧ z = 0 C → Y ∈ V
33 14 adantr ⊢ φ ∧ z = 0 C → t ∈ M ⁡ N ⁡ X ⊕ ˙ M ⁡ N ⁡ Y
34 19 adantr ⊢ φ ∧ z = 0 C → G ∈ F
35 20 adantr ⊢ φ ∧ z = 0 C → M ⁡ N ⁡ X = J ⁡ G
36 22 adantr ⊢ φ ∧ z = 0 C → N ⁡ X ≠ N ⁡ Y
37 23 adantr ⊢ φ ∧ z = 0 C → M ⁡ N ⁡ X - ˙ Y = J ⁡ t
38 25 adantr ⊢ φ ∧ z = 0 C → g ∈ B
39 26 adantr ⊢ φ ∧ z = 0 C → z ∈ M ⁡ N ⁡ Y
40 27 adantr ⊢ φ ∧ z = 0 C → t = g · ˙ G R z
41 28 adantr ⊢ φ ∧ z = 0 C → X ≠ Q
42 29 adantr ⊢ φ ∧ z = 0 C → Y ≠ Q
43 simpr ⊢ φ ∧ z = 0 C → z = 0 C
44 1 2 3 4 5 6 7 30 31 32 11 12 13 33 15 16 17 18 34 35 21 36 37 24 38 39 40 41 42 43 mapdpglem15 ⊢ φ ∧ z = 0 C → N ⁡ X = N ⁡ Y
45 44 ex ⊢ φ → z = 0 C → N ⁡ X = N ⁡ Y
46 45 necon3d ⊢ φ → N ⁡ X ≠ N ⁡ Y → z ≠ 0 C
47 22 46 mpd ⊢ φ → z ≠ 0 C