Metamath Proof Explorer


Theorem mendvsca

Description: A specific scalar multiplication in the module endomorphism algebra. (Contributed by Stefan O'Rear, 3-Sep-2015)

Ref Expression
Hypotheses mendvscafval.a ⊢ A = MEndo ⁡ M
mendvscafval.v ⊢ · ˙ = ⋅ M
mendvscafval.b ⊢ B = Base A
mendvscafval.s ⊢ S = Scalar ⁡ M
mendvscafval.k ⊢ K = Base S
mendvscafval.e ⊢ E = Base M
mendvsca.w ⊢ ∙ ˙ = ⋅ A
Assertion mendvsca ⊢ X ∈ K ∧ Y ∈ B → X ∙ ˙ Y = E × X · ˙ f Y

Proof

Step Hyp Ref Expression
1 mendvscafval.a ⊢ A = MEndo ⁡ M
2 mendvscafval.v ⊢ · ˙ = ⋅ M
3 mendvscafval.b ⊢ B = Base A
4 mendvscafval.s ⊢ S = Scalar ⁡ M
5 mendvscafval.k ⊢ K = Base S
6 mendvscafval.e ⊢ E = Base M
7 mendvsca.w ⊢ ∙ ˙ = ⋅ A
8 sneq ⊢ x = X → x = X
9 8 xpeq2d ⊢ x = X → E × x = E × X
10 id ⊢ y = Y → y = Y
11 9 10 oveqan12d ⊢ x = X ∧ y = Y → E × x · ˙ f y = E × X · ˙ f Y
12 1 2 3 4 5 6 mendvscafval ⊢ ⋅ A = x ∈ K , y ∈ B ⟼ E × x · ˙ f y
13 7 12 eqtri ⊢ ∙ ˙ = x ∈ K , y ∈ B ⟼ E × x · ˙ f y
14 ovex ⊢ E × X · ˙ f Y ∈ V
15 11 13 14 ovmpoa ⊢ X ∈ K ∧ Y ∈ B → X ∙ ˙ Y = E × X · ˙ f Y