Metamath Proof Explorer


Theorem midcom

Description: Commutativity rule for the midpoint. (Contributed by Thierry Arnoux, 2-Dec-2019)

Ref Expression
Hypotheses ismid.p ⊢ P = Base G
ismid.d ⊢ - ˙ = dist ⁡ G
ismid.i ⊢ I = Itv ⁡ G
ismid.g ⊢ φ → G ∈ 𝒢 Tarski
ismid.1 ⊢ φ → G Dim 𝒢 ≥ 2
midcl.1 ⊢ φ → A ∈ P
midcl.2 ⊢ φ → B ∈ P
Assertion midcom ⊢ φ → A mid 𝒢 ⁡ G B = B mid 𝒢 ⁡ G A

Proof

Step Hyp Ref Expression
1 ismid.p ⊢ P = Base G
2 ismid.d ⊢ - ˙ = dist ⁡ G
3 ismid.i ⊢ I = Itv ⁡ G
4 ismid.g ⊢ φ → G ∈ 𝒢 Tarski
5 ismid.1 ⊢ φ → G Dim 𝒢 ≥ 2
6 midcl.1 ⊢ φ → A ∈ P
7 midcl.2 ⊢ φ → B ∈ P
8 eqid ⊢ Line 𝒢 ⁡ G = Line 𝒢 ⁡ G
9 eqid ⊢ pInv 𝒢 ⁡ G = pInv 𝒢 ⁡ G
10 1 2 3 4 5 7 6 midcl ⊢ φ → B mid 𝒢 ⁡ G A ∈ P
11 eqid ⊢ pInv 𝒢 ⁡ G ⁡ B mid 𝒢 ⁡ G A = pInv 𝒢 ⁡ G ⁡ B mid 𝒢 ⁡ G A
12 eqidd ⊢ φ → B mid 𝒢 ⁡ G A = B mid 𝒢 ⁡ G A
13 1 2 3 4 5 7 6 12 midcgr ⊢ φ → B mid 𝒢 ⁡ G A - ˙ B = B mid 𝒢 ⁡ G A - ˙ A
14 1 2 3 4 5 7 6 midbtwn ⊢ φ → B mid 𝒢 ⁡ G A ∈ B I A
15 1 2 3 8 9 4 10 11 6 7 13 14 ismir ⊢ φ → B = pInv 𝒢 ⁡ G ⁡ B mid 𝒢 ⁡ G A ⁡ A
16 1 2 3 4 5 6 7 9 10 ismidb ⊢ φ → B = pInv 𝒢 ⁡ G ⁡ B mid 𝒢 ⁡ G A ⁡ A ↔ A mid 𝒢 ⁡ G B = B mid 𝒢 ⁡ G A
17 15 16 mpbid ⊢ φ → A mid 𝒢 ⁡ G B = B mid 𝒢 ⁡ G A