Metamath Proof Explorer


Theorem miduniq2

Description: If two point inversions commute, they are identical. Theorem 7.19 of Schwabhauser p. 52. (Contributed by Thierry Arnoux, 30-Jul-2019)

Ref Expression
Hypotheses mirval.p ⊢ P = Base G
mirval.d ⊢ - ˙ = dist ⁡ G
mirval.i ⊢ I = Itv ⁡ G
mirval.l ⊢ L = Line 𝒢 ⁡ G
mirval.s ⊢ S = pInv 𝒢 ⁡ G
mirval.g ⊢ φ → G ∈ 𝒢 Tarski
miduniq2.a ⊢ φ → A ∈ P
miduniq2.b ⊢ φ → B ∈ P
miduniq2.x ⊢ φ → X ∈ P
miduniq2.e ⊢ φ → S ⁡ A ⁡ S ⁡ B ⁡ X = S ⁡ B ⁡ S ⁡ A ⁡ X
Assertion miduniq2 ⊢ φ → A = B

Proof

Step Hyp Ref Expression
1 mirval.p ⊢ P = Base G
2 mirval.d ⊢ - ˙ = dist ⁡ G
3 mirval.i ⊢ I = Itv ⁡ G
4 mirval.l ⊢ L = Line 𝒢 ⁡ G
5 mirval.s ⊢ S = pInv 𝒢 ⁡ G
6 mirval.g ⊢ φ → G ∈ 𝒢 Tarski
7 miduniq2.a ⊢ φ → A ∈ P
8 miduniq2.b ⊢ φ → B ∈ P
9 miduniq2.x ⊢ φ → X ∈ P
10 miduniq2.e ⊢ φ → S ⁡ A ⁡ S ⁡ B ⁡ X = S ⁡ B ⁡ S ⁡ A ⁡ X
11 eqid ⊢ S ⁡ B = S ⁡ B
12 1 2 3 4 5 6 8 11 mirf ⊢ φ → S ⁡ B : P ⟶ P
13 12 7 ffvelcdmd ⊢ φ → S ⁡ B ⁡ A ∈ P
14 eqid ⊢ S ⁡ B ⁡ A = S ⁡ B ⁡ A
15 eqid ⊢ S ⁡ B ⁡ S ⁡ B ⁡ X = S ⁡ B ⁡ S ⁡ B ⁡ X
16 eqid ⊢ S ⁡ B ⁡ S ⁡ B ⁡ S ⁡ A ⁡ X = S ⁡ B ⁡ S ⁡ B ⁡ S ⁡ A ⁡ X
17 12 9 ffvelcdmd ⊢ φ → S ⁡ B ⁡ X ∈ P
18 eqid ⊢ S ⁡ A = S ⁡ A
19 1 2 3 4 5 6 7 18 9 mircl ⊢ φ → S ⁡ A ⁡ X ∈ P
20 12 19 ffvelcdmd ⊢ φ → S ⁡ B ⁡ S ⁡ A ⁡ X ∈ P
21 1 2 3 4 5 6 11 14 15 16 8 7 17 20 10 mirauto ⊢ φ → S ⁡ S ⁡ B ⁡ A ⁡ S ⁡ B ⁡ S ⁡ B ⁡ X = S ⁡ B ⁡ S ⁡ B ⁡ S ⁡ A ⁡ X
22 1 2 3 4 5 6 8 11 9 mirmir ⊢ φ → S ⁡ B ⁡ S ⁡ B ⁡ X = X
23 22 fveq2d ⊢ φ → S ⁡ S ⁡ B ⁡ A ⁡ S ⁡ B ⁡ S ⁡ B ⁡ X = S ⁡ S ⁡ B ⁡ A ⁡ X
24 1 2 3 4 5 6 8 11 19 mirmir ⊢ φ → S ⁡ B ⁡ S ⁡ B ⁡ S ⁡ A ⁡ X = S ⁡ A ⁡ X
25 21 23 24 3eqtr3d ⊢ φ → S ⁡ S ⁡ B ⁡ A ⁡ X = S ⁡ A ⁡ X
26 1 2 3 4 5 6 13 7 9 25 miduniq1 ⊢ φ → S ⁡ B ⁡ A = A
27 1 2 3 4 5 6 8 11 7 mirinv ⊢ φ → S ⁡ B ⁡ A = A ↔ B = A
28 26 27 mpbid ⊢ φ → B = A
29 28 eqcomd ⊢ φ → A = B