Metamath Proof Explorer


Theorem mirf

Description: Point inversion as function. (Contributed by Thierry Arnoux, 30-May-2019)

Ref Expression
Hypotheses mirval.p ⊢ P = Base G
mirval.d ⊢ - ˙ = dist ⁡ G
mirval.i ⊢ I = Itv ⁡ G
mirval.l ⊢ L = Line 𝒢 ⁡ G
mirval.s ⊢ S = pInv 𝒢 ⁡ G
mirval.g ⊢ φ → G ∈ 𝒢 Tarski
mirval.a ⊢ φ → A ∈ P
mirfv.m ⊢ M = S ⁡ A
Assertion mirf ⊢ φ → M : P ⟶ P

Proof

Step Hyp Ref Expression
1 mirval.p ⊢ P = Base G
2 mirval.d ⊢ - ˙ = dist ⁡ G
3 mirval.i ⊢ I = Itv ⁡ G
4 mirval.l ⊢ L = Line 𝒢 ⁡ G
5 mirval.s ⊢ S = pInv 𝒢 ⁡ G
6 mirval.g ⊢ φ → G ∈ 𝒢 Tarski
7 mirval.a ⊢ φ → A ∈ P
8 mirfv.m ⊢ M = S ⁡ A
9 riotaex ⊢ ι z ∈ P | A - ˙ z = A - ˙ y ∧ A ∈ z I y ∈ V
10 9 a1i ⊢ φ ∧ y ∈ P → ι z ∈ P | A - ˙ z = A - ˙ y ∧ A ∈ z I y ∈ V
11 1 2 3 4 5 6 7 mirval ⊢ φ → S ⁡ A = y ∈ P ⟼ ι z ∈ P | A - ˙ z = A - ˙ y ∧ A ∈ z I y
12 8 11 eqtrid ⊢ φ → M = y ∈ P ⟼ ι z ∈ P | A - ˙ z = A - ˙ y ∧ A ∈ z I y
13 6 adantr ⊢ φ ∧ x ∈ P → G ∈ 𝒢 Tarski
14 7 adantr ⊢ φ ∧ x ∈ P → A ∈ P
15 simpr ⊢ φ ∧ x ∈ P → x ∈ P
16 1 2 3 4 5 13 14 8 15 mirfv ⊢ φ ∧ x ∈ P → M ⁡ x = ι z ∈ P | A - ˙ z = A - ˙ x ∧ A ∈ z I x
17 1 2 3 13 15 14 mirreu3 ⊢ φ ∧ x ∈ P → ∃! z ∈ P A - ˙ z = A - ˙ x ∧ A ∈ z I x
18 riotacl ⊢ ∃! z ∈ P A - ˙ z = A - ˙ x ∧ A ∈ z I x → ι z ∈ P | A - ˙ z = A - ˙ x ∧ A ∈ z I x ∈ P
19 17 18 syl ⊢ φ ∧ x ∈ P → ι z ∈ P | A - ˙ z = A - ˙ x ∧ A ∈ z I x ∈ P
20 16 19 eqeltrd ⊢ φ ∧ x ∈ P → M ⁡ x ∈ P
21 10 12 20 fmpt2d ⊢ φ → M : P ⟶ P