Metamath Proof Explorer


Theorem mulgt0con2d

Description: Lemma for mulgt0b1d and contrapositive of mulgt0 . (Contributed by SN, 26-Jun-2024)

Ref Expression
Hypotheses mulgt0con2d.a ⊢ φ → A ∈ ℝ
mulgt0con2d.b ⊢ φ → B ∈ ℝ
mulgt0con2d.1 ⊢ φ → 0 < A
mulgt0con2d.2 ⊢ φ → A ⁢ B < 0
Assertion mulgt0con2d ⊢ φ → B < 0

Proof

Step Hyp Ref Expression
1 mulgt0con2d.a ⊢ φ → A ∈ ℝ
2 mulgt0con2d.b ⊢ φ → B ∈ ℝ
3 mulgt0con2d.1 ⊢ φ → 0 < A
4 mulgt0con2d.2 ⊢ φ → A ⁢ B < 0
5 1 2 remulcld ⊢ φ → A ⁢ B ∈ ℝ
6 1 adantr ⊢ φ ∧ 0 < B → A ∈ ℝ
7 2 adantr ⊢ φ ∧ 0 < B → B ∈ ℝ
8 3 adantr ⊢ φ ∧ 0 < B → 0 < A
9 simpr ⊢ φ ∧ 0 < B → 0 < B
10 6 7 8 9 mulgt0d ⊢ φ ∧ 0 < B → 0 < A ⁢ B
11 10 ex ⊢ φ → 0 < B → 0 < A ⁢ B
12 remul01 ⊢ A ∈ ℝ → A ⋅ 0 = 0
13 1 12 syl ⊢ φ → A ⋅ 0 = 0
14 oveq2 ⊢ B = 0 → A ⁢ B = A ⋅ 0
15 14 eqeq1d ⊢ B = 0 → A ⁢ B = 0 ↔ A ⋅ 0 = 0
16 13 15 syl5ibrcom ⊢ φ → B = 0 → A ⁢ B = 0
17 2 5 11 16 mulgt0con1dlem ⊢ φ → A ⁢ B < 0 → B < 0
18 4 17 mpd ⊢ φ → B < 0