Metamath Proof Explorer


Theorem nm2dif

Description: Inequality for the difference of norms. (Contributed by Mario Carneiro, 6-Oct-2015)

Ref Expression
Hypotheses nmf.x ⊢ X = Base G
nmf.n ⊢ N = norm ⁡ G
nmmtri.m ⊢ - ˙ = - G
Assertion nm2dif ⊢ G ∈ NrmGrp ∧ A ∈ X ∧ B ∈ X → N ⁡ A − N ⁡ B ≤ N ⁡ A - ˙ B

Proof

Step Hyp Ref Expression
1 nmf.x ⊢ X = Base G
2 nmf.n ⊢ N = norm ⁡ G
3 nmmtri.m ⊢ - ˙ = - G
4 1 2 nmcl ⊢ G ∈ NrmGrp ∧ A ∈ X → N ⁡ A ∈ ℝ
5 4 3adant3 ⊢ G ∈ NrmGrp ∧ A ∈ X ∧ B ∈ X → N ⁡ A ∈ ℝ
6 1 2 nmcl ⊢ G ∈ NrmGrp ∧ B ∈ X → N ⁡ B ∈ ℝ
7 6 3adant2 ⊢ G ∈ NrmGrp ∧ A ∈ X ∧ B ∈ X → N ⁡ B ∈ ℝ
8 5 7 resubcld ⊢ G ∈ NrmGrp ∧ A ∈ X ∧ B ∈ X → N ⁡ A − N ⁡ B ∈ ℝ
9 8 recnd ⊢ G ∈ NrmGrp ∧ A ∈ X ∧ B ∈ X → N ⁡ A − N ⁡ B ∈ ℂ
10 9 abscld ⊢ G ∈ NrmGrp ∧ A ∈ X ∧ B ∈ X → N ⁡ A − N ⁡ B ∈ ℝ
11 simp1 ⊢ G ∈ NrmGrp ∧ A ∈ X ∧ B ∈ X → G ∈ NrmGrp
12 ngpgrp ⊢ G ∈ NrmGrp → G ∈ Grp
13 1 3 grpsubcl ⊢ G ∈ Grp ∧ A ∈ X ∧ B ∈ X → A - ˙ B ∈ X
14 12 13 syl3an1 ⊢ G ∈ NrmGrp ∧ A ∈ X ∧ B ∈ X → A - ˙ B ∈ X
15 1 2 nmcl ⊢ G ∈ NrmGrp ∧ A - ˙ B ∈ X → N ⁡ A - ˙ B ∈ ℝ
16 11 14 15 syl2anc ⊢ G ∈ NrmGrp ∧ A ∈ X ∧ B ∈ X → N ⁡ A - ˙ B ∈ ℝ
17 8 leabsd ⊢ G ∈ NrmGrp ∧ A ∈ X ∧ B ∈ X → N ⁡ A − N ⁡ B ≤ N ⁡ A − N ⁡ B
18 1 2 3 nmrtri ⊢ G ∈ NrmGrp ∧ A ∈ X ∧ B ∈ X → N ⁡ A − N ⁡ B ≤ N ⁡ A - ˙ B
19 8 10 16 17 18 letrd ⊢ G ∈ NrmGrp ∧ A ∈ X ∧ B ∈ X → N ⁡ A − N ⁡ B ≤ N ⁡ A - ˙ B