Metamath Proof Explorer


Theorem nn0enn0ex

Description: For each even nonnegative integer there is a nonnegative integer which, multiplied by 2, results in the even nonnegative integer. (Contributed by AV, 30-May-2020)

Ref Expression
Assertion nn0enn0ex ⊢ N ∈ ℕ 0 ∧ N 2 ∈ ℕ 0 → ∃ m ∈ ℕ 0 N = 2 ⁢ m

Proof

Step Hyp Ref Expression
1 simpr ⊢ N ∈ ℕ 0 ∧ N 2 ∈ ℕ 0 → N 2 ∈ ℕ 0
2 oveq2 ⊢ m = N 2 → 2 ⁢ m = 2 ⁢ N 2
3 2 adantl ⊢ N ∈ ℕ 0 ∧ N 2 ∈ ℕ 0 ∧ m = N 2 → 2 ⁢ m = 2 ⁢ N 2
4 3 eqeq2d ⊢ N ∈ ℕ 0 ∧ N 2 ∈ ℕ 0 ∧ m = N 2 → N = 2 ⁢ m ↔ N = 2 ⁢ N 2
5 nn0cn ⊢ N ∈ ℕ 0 → N ∈ ℂ
6 2cnd ⊢ N ∈ ℕ 0 → 2 ∈ ℂ
7 2ne0 ⊢ 2 ≠ 0
8 7 a1i ⊢ N ∈ ℕ 0 → 2 ≠ 0
9 divcan2 ⊢ N ∈ ℂ ∧ 2 ∈ ℂ ∧ 2 ≠ 0 → 2 ⁢ N 2 = N
10 9 eqcomd ⊢ N ∈ ℂ ∧ 2 ∈ ℂ ∧ 2 ≠ 0 → N = 2 ⁢ N 2
11 5 6 8 10 syl3anc ⊢ N ∈ ℕ 0 → N = 2 ⁢ N 2
12 11 adantr ⊢ N ∈ ℕ 0 ∧ N 2 ∈ ℕ 0 → N = 2 ⁢ N 2
13 1 4 12 rspcedvd ⊢ N ∈ ℕ 0 ∧ N 2 ∈ ℕ 0 → ∃ m ∈ ℕ 0 N = 2 ⁢ m