Metamath Proof Explorer


Theorem nprmmul2

Description: Special factorization of a non-prime integer greater than 3. (Contributed by AV, 6-Apr-2026)

Ref Expression
Assertion nprmmul2 ⊢ N ∈ ℤ ≥ 4 → N ∉ ℙ ↔ ∃ a ∈ 2 ..^ N ∃ b ∈ 2 ..^ N a ≤ b ∧ N = a ⁢ b

Proof

Step Hyp Ref Expression
1 nprmmul1 ⊢ N ∈ ℤ ≥ 4 → N ∉ ℙ ↔ ∃ m ∈ 2 ..^ N ∃ n ∈ 2 ..^ N N = m ⁢ n
2 breq1 ⊢ a = n → a ≤ b ↔ n ≤ b
3 oveq1 ⊢ a = n → a ⁢ b = n ⁢ b
4 3 eqeq2d ⊢ a = n → N = a ⁢ b ↔ N = n ⁢ b
5 2 4 anbi12d ⊢ a = n → a ≤ b ∧ N = a ⁢ b ↔ n ≤ b ∧ N = n ⁢ b
6 breq2 ⊢ b = m → n ≤ b ↔ n ≤ m
7 oveq2 ⊢ b = m → n ⁢ b = n ⁢ m
8 7 eqeq2d ⊢ b = m → N = n ⁢ b ↔ N = n ⁢ m
9 6 8 anbi12d ⊢ b = m → n ≤ b ∧ N = n ⁢ b ↔ n ≤ m ∧ N = n ⁢ m
10 simp1rr ⊢ N ∈ ℤ ≥ 4 ∧ m ∈ 2 ..^ N ∧ n ∈ 2 ..^ N ∧ n ≤ m ∧ N = m ⁢ n → n ∈ 2 ..^ N
11 simp1rl ⊢ N ∈ ℤ ≥ 4 ∧ m ∈ 2 ..^ N ∧ n ∈ 2 ..^ N ∧ n ≤ m ∧ N = m ⁢ n → m ∈ 2 ..^ N
12 simp2 ⊢ N ∈ ℤ ≥ 4 ∧ m ∈ 2 ..^ N ∧ n ∈ 2 ..^ N ∧ n ≤ m ∧ N = m ⁢ n → n ≤ m
13 elfzo2nn ⊢ m ∈ 2 ..^ N → m ∈ ℕ
14 elfzo2nn ⊢ n ∈ 2 ..^ N → n ∈ ℕ
15 nnmulcom ⊢ m ∈ ℕ ∧ n ∈ ℕ → m ⁢ n = n ⁢ m
16 13 14 15 syl2an ⊢ m ∈ 2 ..^ N ∧ n ∈ 2 ..^ N → m ⁢ n = n ⁢ m
17 16 eqeq2d ⊢ m ∈ 2 ..^ N ∧ n ∈ 2 ..^ N → N = m ⁢ n ↔ N = n ⁢ m
18 17 biimpd ⊢ m ∈ 2 ..^ N ∧ n ∈ 2 ..^ N → N = m ⁢ n → N = n ⁢ m
19 18 adantl ⊢ N ∈ ℤ ≥ 4 ∧ m ∈ 2 ..^ N ∧ n ∈ 2 ..^ N → N = m ⁢ n → N = n ⁢ m
20 19 imp ⊢ N ∈ ℤ ≥ 4 ∧ m ∈ 2 ..^ N ∧ n ∈ 2 ..^ N ∧ N = m ⁢ n → N = n ⁢ m
21 20 3adant2 ⊢ N ∈ ℤ ≥ 4 ∧ m ∈ 2 ..^ N ∧ n ∈ 2 ..^ N ∧ n ≤ m ∧ N = m ⁢ n → N = n ⁢ m
22 12 21 jca ⊢ N ∈ ℤ ≥ 4 ∧ m ∈ 2 ..^ N ∧ n ∈ 2 ..^ N ∧ n ≤ m ∧ N = m ⁢ n → n ≤ m ∧ N = n ⁢ m
23 5 9 10 11 22 2rspcedvdw ⊢ N ∈ ℤ ≥ 4 ∧ m ∈ 2 ..^ N ∧ n ∈ 2 ..^ N ∧ n ≤ m ∧ N = m ⁢ n → ∃ a ∈ 2 ..^ N ∃ b ∈ 2 ..^ N a ≤ b ∧ N = a ⁢ b
24 23 3exp ⊢ N ∈ ℤ ≥ 4 ∧ m ∈ 2 ..^ N ∧ n ∈ 2 ..^ N → n ≤ m → N = m ⁢ n → ∃ a ∈ 2 ..^ N ∃ b ∈ 2 ..^ N a ≤ b ∧ N = a ⁢ b
25 breq1 ⊢ a = m → a ≤ b ↔ m ≤ b
26 oveq1 ⊢ a = m → a ⁢ b = m ⁢ b
27 26 eqeq2d ⊢ a = m → N = a ⁢ b ↔ N = m ⁢ b
28 25 27 anbi12d ⊢ a = m → a ≤ b ∧ N = a ⁢ b ↔ m ≤ b ∧ N = m ⁢ b
29 breq2 ⊢ b = n → m ≤ b ↔ m ≤ n
30 oveq2 ⊢ b = n → m ⁢ b = m ⁢ n
31 30 eqeq2d ⊢ b = n → N = m ⁢ b ↔ N = m ⁢ n
32 29 31 anbi12d ⊢ b = n → m ≤ b ∧ N = m ⁢ b ↔ m ≤ n ∧ N = m ⁢ n
33 simp1rl ⊢ N ∈ ℤ ≥ 4 ∧ m ∈ 2 ..^ N ∧ n ∈ 2 ..^ N ∧ m ≤ n ∧ N = m ⁢ n → m ∈ 2 ..^ N
34 simp1rr ⊢ N ∈ ℤ ≥ 4 ∧ m ∈ 2 ..^ N ∧ n ∈ 2 ..^ N ∧ m ≤ n ∧ N = m ⁢ n → n ∈ 2 ..^ N
35 3simpc ⊢ N ∈ ℤ ≥ 4 ∧ m ∈ 2 ..^ N ∧ n ∈ 2 ..^ N ∧ m ≤ n ∧ N = m ⁢ n → m ≤ n ∧ N = m ⁢ n
36 28 32 33 34 35 2rspcedvdw ⊢ N ∈ ℤ ≥ 4 ∧ m ∈ 2 ..^ N ∧ n ∈ 2 ..^ N ∧ m ≤ n ∧ N = m ⁢ n → ∃ a ∈ 2 ..^ N ∃ b ∈ 2 ..^ N a ≤ b ∧ N = a ⁢ b
37 36 3exp ⊢ N ∈ ℤ ≥ 4 ∧ m ∈ 2 ..^ N ∧ n ∈ 2 ..^ N → m ≤ n → N = m ⁢ n → ∃ a ∈ 2 ..^ N ∃ b ∈ 2 ..^ N a ≤ b ∧ N = a ⁢ b
38 elfzoelz ⊢ m ∈ 2 ..^ N → m ∈ ℤ
39 38 zred ⊢ m ∈ 2 ..^ N → m ∈ ℝ
40 elfzoelz ⊢ n ∈ 2 ..^ N → n ∈ ℤ
41 40 zred ⊢ n ∈ 2 ..^ N → n ∈ ℝ
42 39 41 anim12ci ⊢ m ∈ 2 ..^ N ∧ n ∈ 2 ..^ N → n ∈ ℝ ∧ m ∈ ℝ
43 42 adantl ⊢ N ∈ ℤ ≥ 4 ∧ m ∈ 2 ..^ N ∧ n ∈ 2 ..^ N → n ∈ ℝ ∧ m ∈ ℝ
44 letric ⊢ n ∈ ℝ ∧ m ∈ ℝ → n ≤ m ∨ m ≤ n
45 43 44 syl ⊢ N ∈ ℤ ≥ 4 ∧ m ∈ 2 ..^ N ∧ n ∈ 2 ..^ N → n ≤ m ∨ m ≤ n
46 24 37 45 mpjaod ⊢ N ∈ ℤ ≥ 4 ∧ m ∈ 2 ..^ N ∧ n ∈ 2 ..^ N → N = m ⁢ n → ∃ a ∈ 2 ..^ N ∃ b ∈ 2 ..^ N a ≤ b ∧ N = a ⁢ b
47 46 rexlimdvva ⊢ N ∈ ℤ ≥ 4 → ∃ m ∈ 2 ..^ N ∃ n ∈ 2 ..^ N N = m ⁢ n → ∃ a ∈ 2 ..^ N ∃ b ∈ 2 ..^ N a ≤ b ∧ N = a ⁢ b
48 oveq1 ⊢ m = a → m ⁢ n = a ⁢ n
49 48 eqeq2d ⊢ m = a → N = m ⁢ n ↔ N = a ⁢ n
50 oveq2 ⊢ n = b → a ⁢ n = a ⁢ b
51 50 eqeq2d ⊢ n = b → N = a ⁢ n ↔ N = a ⁢ b
52 simplrl ⊢ N ∈ ℤ ≥ 4 ∧ a ∈ 2 ..^ N ∧ b ∈ 2 ..^ N ∧ N = a ⁢ b → a ∈ 2 ..^ N
53 simplrr ⊢ N ∈ ℤ ≥ 4 ∧ a ∈ 2 ..^ N ∧ b ∈ 2 ..^ N ∧ N = a ⁢ b → b ∈ 2 ..^ N
54 simpr ⊢ N ∈ ℤ ≥ 4 ∧ a ∈ 2 ..^ N ∧ b ∈ 2 ..^ N ∧ N = a ⁢ b → N = a ⁢ b
55 49 51 52 53 54 2rspcedvdw ⊢ N ∈ ℤ ≥ 4 ∧ a ∈ 2 ..^ N ∧ b ∈ 2 ..^ N ∧ N = a ⁢ b → ∃ m ∈ 2 ..^ N ∃ n ∈ 2 ..^ N N = m ⁢ n
56 55 ex ⊢ N ∈ ℤ ≥ 4 ∧ a ∈ 2 ..^ N ∧ b ∈ 2 ..^ N → N = a ⁢ b → ∃ m ∈ 2 ..^ N ∃ n ∈ 2 ..^ N N = m ⁢ n
57 56 adantld ⊢ N ∈ ℤ ≥ 4 ∧ a ∈ 2 ..^ N ∧ b ∈ 2 ..^ N → a ≤ b ∧ N = a ⁢ b → ∃ m ∈ 2 ..^ N ∃ n ∈ 2 ..^ N N = m ⁢ n
58 57 rexlimdvva ⊢ N ∈ ℤ ≥ 4 → ∃ a ∈ 2 ..^ N ∃ b ∈ 2 ..^ N a ≤ b ∧ N = a ⁢ b → ∃ m ∈ 2 ..^ N ∃ n ∈ 2 ..^ N N = m ⁢ n
59 47 58 impbid ⊢ N ∈ ℤ ≥ 4 → ∃ m ∈ 2 ..^ N ∃ n ∈ 2 ..^ N N = m ⁢ n ↔ ∃ a ∈ 2 ..^ N ∃ b ∈ 2 ..^ N a ≤ b ∧ N = a ⁢ b
60 1 59 bitrd ⊢ N ∈ ℤ ≥ 4 → N ∉ ℙ ↔ ∃ a ∈ 2 ..^ N ∃ b ∈ 2 ..^ N a ≤ b ∧ N = a ⁢ b