Metamath Proof Explorer


Theorem oddibas

Description: Lemma 1 for oddinmgm : The base set of M is the set of all odd integers. (Contributed by AV, 3-Feb-2020)

Ref Expression
Hypotheses oddinmgm.e ⊢ O = z ∈ ℤ | ∃ x ∈ ℤ z = 2 ⁢ x + 1
oddinmgm.r ⊢ M = ℂ fld ↾ 𝑠 O
Assertion oddibas ⊢ O = Base M

Proof

Step Hyp Ref Expression
1 oddinmgm.e ⊢ O = z ∈ ℤ | ∃ x ∈ ℤ z = 2 ⁢ x + 1
2 oddinmgm.r ⊢ M = ℂ fld ↾ 𝑠 O
3 ssrab2 ⊢ z ∈ ℤ | ∃ x ∈ ℤ z = 2 ⁢ x + 1 ⊆ ℤ
4 1 3 eqsstri ⊢ O ⊆ ℤ
5 zsscn ⊢ ℤ ⊆ ℂ
6 4 5 sstri ⊢ O ⊆ ℂ
7 2 cnfldsrngbas ⊢ O ⊆ ℂ → O = Base M
8 6 7 ax-mp ⊢ O = Base M