Metamath Proof Explorer


Theorem osumcor2i

Description: Corollary of osumi , showing it holds under the weaker hypothesis that A and B commute. (Contributed by NM, 6-Dec-2000) (New usage is discouraged.)

Ref Expression
Hypotheses osum.1 ⊢ A ∈ C ℋ
osum.2 ⊢ B ∈ C ℋ
Assertion osumcor2i ⊢ A 𝐶 ℋ B → A + ℋ B = A ∨ ℋ B

Proof

Step Hyp Ref Expression
1 osum.1 ⊢ A ∈ C ℋ
2 osum.2 ⊢ B ∈ C ℋ
3 1 2 cmcm2i ⊢ A 𝐶 ℋ B ↔ A 𝐶 ℋ ⊥ ⁡ B
4 2 choccli ⊢ ⊥ ⁡ B ∈ C ℋ
5 1 4 cmbr4i ⊢ A 𝐶 ℋ ⊥ ⁡ B ↔ A ∩ ⊥ ⁡ A ∨ ℋ ⊥ ⁡ B ⊆ ⊥ ⁡ B
6 3 5 bitri ⊢ A 𝐶 ℋ B ↔ A ∩ ⊥ ⁡ A ∨ ℋ ⊥ ⁡ B ⊆ ⊥ ⁡ B
7 1 choccli ⊢ ⊥ ⁡ A ∈ C ℋ
8 7 4 chjcli ⊢ ⊥ ⁡ A ∨ ℋ ⊥ ⁡ B ∈ C ℋ
9 1 8 chincli ⊢ A ∩ ⊥ ⁡ A ∨ ℋ ⊥ ⁡ B ∈ C ℋ
10 9 2 osumi ⊢ A ∩ ⊥ ⁡ A ∨ ℋ ⊥ ⁡ B ⊆ ⊥ ⁡ B → A ∩ ⊥ ⁡ A ∨ ℋ ⊥ ⁡ B + ℋ B = A ∩ ⊥ ⁡ A ∨ ℋ ⊥ ⁡ B ∨ ℋ B
11 7 4 chjcomi ⊢ ⊥ ⁡ A ∨ ℋ ⊥ ⁡ B = ⊥ ⁡ B ∨ ℋ ⊥ ⁡ A
12 11 ineq2i ⊢ A ∩ ⊥ ⁡ A ∨ ℋ ⊥ ⁡ B = A ∩ ⊥ ⁡ B ∨ ℋ ⊥ ⁡ A
13 12 oveq1i ⊢ A ∩ ⊥ ⁡ A ∨ ℋ ⊥ ⁡ B ∨ ℋ B = A ∩ ⊥ ⁡ B ∨ ℋ ⊥ ⁡ A ∨ ℋ B
14 4 7 chjcli ⊢ ⊥ ⁡ B ∨ ℋ ⊥ ⁡ A ∈ C ℋ
15 1 14 chincli ⊢ A ∩ ⊥ ⁡ B ∨ ℋ ⊥ ⁡ A ∈ C ℋ
16 15 2 chjcomi ⊢ A ∩ ⊥ ⁡ B ∨ ℋ ⊥ ⁡ A ∨ ℋ B = B ∨ ℋ A ∩ ⊥ ⁡ B ∨ ℋ ⊥ ⁡ A
17 13 16 eqtri ⊢ A ∩ ⊥ ⁡ A ∨ ℋ ⊥ ⁡ B ∨ ℋ B = B ∨ ℋ A ∩ ⊥ ⁡ B ∨ ℋ ⊥ ⁡ A
18 2 1 pjoml4i ⊢ B ∨ ℋ A ∩ ⊥ ⁡ B ∨ ℋ ⊥ ⁡ A = B ∨ ℋ A
19 2 1 chjcomi ⊢ B ∨ ℋ A = A ∨ ℋ B
20 18 19 eqtri ⊢ B ∨ ℋ A ∩ ⊥ ⁡ B ∨ ℋ ⊥ ⁡ A = A ∨ ℋ B
21 17 20 eqtri ⊢ A ∩ ⊥ ⁡ A ∨ ℋ ⊥ ⁡ B ∨ ℋ B = A ∨ ℋ B
22 21 eqeq2i ⊢ A ∩ ⊥ ⁡ A ∨ ℋ ⊥ ⁡ B + ℋ B = A ∩ ⊥ ⁡ A ∨ ℋ ⊥ ⁡ B ∨ ℋ B ↔ A ∩ ⊥ ⁡ A ∨ ℋ ⊥ ⁡ B + ℋ B = A ∨ ℋ B
23 inss1 ⊢ A ∩ ⊥ ⁡ A ∨ ℋ ⊥ ⁡ B ⊆ A
24 9 chshii ⊢ A ∩ ⊥ ⁡ A ∨ ℋ ⊥ ⁡ B ∈ S ℋ
25 1 chshii ⊢ A ∈ S ℋ
26 2 chshii ⊢ B ∈ S ℋ
27 24 25 26 shlessi ⊢ A ∩ ⊥ ⁡ A ∨ ℋ ⊥ ⁡ B ⊆ A → A ∩ ⊥ ⁡ A ∨ ℋ ⊥ ⁡ B + ℋ B ⊆ A + ℋ B
28 23 27 ax-mp ⊢ A ∩ ⊥ ⁡ A ∨ ℋ ⊥ ⁡ B + ℋ B ⊆ A + ℋ B
29 sseq1 ⊢ A ∩ ⊥ ⁡ A ∨ ℋ ⊥ ⁡ B + ℋ B = A ∨ ℋ B → A ∩ ⊥ ⁡ A ∨ ℋ ⊥ ⁡ B + ℋ B ⊆ A + ℋ B ↔ A ∨ ℋ B ⊆ A + ℋ B
30 28 29 mpbii ⊢ A ∩ ⊥ ⁡ A ∨ ℋ ⊥ ⁡ B + ℋ B = A ∨ ℋ B → A ∨ ℋ B ⊆ A + ℋ B
31 22 30 sylbi ⊢ A ∩ ⊥ ⁡ A ∨ ℋ ⊥ ⁡ B + ℋ B = A ∩ ⊥ ⁡ A ∨ ℋ ⊥ ⁡ B ∨ ℋ B → A ∨ ℋ B ⊆ A + ℋ B
32 10 31 syl ⊢ A ∩ ⊥ ⁡ A ∨ ℋ ⊥ ⁡ B ⊆ ⊥ ⁡ B → A ∨ ℋ B ⊆ A + ℋ B
33 6 32 sylbi ⊢ A 𝐶 ℋ B → A ∨ ℋ B ⊆ A + ℋ B
34 1 2 chsleji ⊢ A + ℋ B ⊆ A ∨ ℋ B
35 33 34 jctil ⊢ A 𝐶 ℋ B → A + ℋ B ⊆ A ∨ ℋ B ∧ A ∨ ℋ B ⊆ A + ℋ B
36 eqss ⊢ A + ℋ B = A ∨ ℋ B ↔ A + ℋ B ⊆ A ∨ ℋ B ∧ A ∨ ℋ B ⊆ A + ℋ B
37 35 36 sylibr ⊢ A 𝐶 ℋ B → A + ℋ B = A ∨ ℋ B