Metamath Proof Explorer


Theorem pgrpsubgsymg

Description: Every permutation group is a subgroup of the corresponding symmetric group. (Contributed by AV, 14-Mar-2019) (Revised by AV, 30-Mar-2024)

Ref Expression
Hypotheses pgrpsubgsymgbi.g ⊢ G = SymGrp ⁡ A
pgrpsubgsymgbi.b ⊢ B = Base G
pgrpsubgsymg.c ⊢ F = Base P
Assertion pgrpsubgsymg ⊢ A ∈ V → P ∈ Grp ∧ F ⊆ B ∧ + P = f ∈ F , g ∈ F ⟼ f ∘ g → F ∈ SubGrp ⁡ G

Proof

Step Hyp Ref Expression
1 pgrpsubgsymgbi.g ⊢ G = SymGrp ⁡ A
2 pgrpsubgsymgbi.b ⊢ B = Base G
3 pgrpsubgsymg.c ⊢ F = Base P
4 1 symggrp ⊢ A ∈ V → G ∈ Grp
5 simp1 ⊢ P ∈ Grp ∧ F ⊆ B ∧ + P = f ∈ F , g ∈ F ⟼ f ∘ g → P ∈ Grp
6 4 5 anim12i ⊢ A ∈ V ∧ P ∈ Grp ∧ F ⊆ B ∧ + P = f ∈ F , g ∈ F ⟼ f ∘ g → G ∈ Grp ∧ P ∈ Grp
7 simp2 ⊢ P ∈ Grp ∧ F ⊆ B ∧ + P = f ∈ F , g ∈ F ⟼ f ∘ g → F ⊆ B
8 simp3 ⊢ P ∈ Grp ∧ F ⊆ B ∧ + P = f ∈ F , g ∈ F ⟼ f ∘ g → + P = f ∈ F , g ∈ F ⟼ f ∘ g
9 1 2 symgbasmap ⊢ f ∈ B → f ∈ A A
10 9 ssriv ⊢ B ⊆ A A
11 sstr ⊢ F ⊆ B ∧ B ⊆ A A → F ⊆ A A
12 10 11 mpan2 ⊢ F ⊆ B → F ⊆ A A
13 resmpo ⊢ F ⊆ A A ∧ F ⊆ A A → f ∈ A A , g ∈ A A ⟼ f ∘ g ↾ F × F = f ∈ F , g ∈ F ⟼ f ∘ g
14 13 anidms ⊢ F ⊆ A A → f ∈ A A , g ∈ A A ⟼ f ∘ g ↾ F × F = f ∈ F , g ∈ F ⟼ f ∘ g
15 12 14 syl ⊢ F ⊆ B → f ∈ A A , g ∈ A A ⟼ f ∘ g ↾ F × F = f ∈ F , g ∈ F ⟼ f ∘ g
16 eqid ⊢ A A = A A
17 eqid ⊢ + G = + G
18 1 16 17 symgplusg ⊢ + G = f ∈ A A , g ∈ A A ⟼ f ∘ g
19 18 eqcomi ⊢ f ∈ A A , g ∈ A A ⟼ f ∘ g = + G
20 19 reseq1i ⊢ f ∈ A A , g ∈ A A ⟼ f ∘ g ↾ F × F = + G ↾ F × F
21 15 20 eqtr3di ⊢ F ⊆ B → f ∈ F , g ∈ F ⟼ f ∘ g = + G ↾ F × F
22 21 3ad2ant2 ⊢ P ∈ Grp ∧ F ⊆ B ∧ + P = f ∈ F , g ∈ F ⟼ f ∘ g → f ∈ F , g ∈ F ⟼ f ∘ g = + G ↾ F × F
23 8 22 eqtrd ⊢ P ∈ Grp ∧ F ⊆ B ∧ + P = f ∈ F , g ∈ F ⟼ f ∘ g → + P = + G ↾ F × F
24 7 23 jca ⊢ P ∈ Grp ∧ F ⊆ B ∧ + P = f ∈ F , g ∈ F ⟼ f ∘ g → F ⊆ B ∧ + P = + G ↾ F × F
25 24 adantl ⊢ A ∈ V ∧ P ∈ Grp ∧ F ⊆ B ∧ + P = f ∈ F , g ∈ F ⟼ f ∘ g → F ⊆ B ∧ + P = + G ↾ F × F
26 2 3 grpissubg ⊢ G ∈ Grp ∧ P ∈ Grp → F ⊆ B ∧ + P = + G ↾ F × F → F ∈ SubGrp ⁡ G
27 6 25 26 sylc ⊢ A ∈ V ∧ P ∈ Grp ∧ F ⊆ B ∧ + P = f ∈ F , g ∈ F ⟼ f ∘ g → F ∈ SubGrp ⁡ G
28 27 ex ⊢ A ∈ V → P ∈ Grp ∧ F ⊆ B ∧ + P = f ∈ F , g ∈ F ⟼ f ∘ g → F ∈ SubGrp ⁡ G