Metamath Proof Explorer


Theorem ply1ascl

Description: The univariate polynomial ring inherits the multivariate ring's scalar function. (Contributed by Stefan O'Rear, 28-Mar-2015) (Proof shortened by Fan Zheng, 26-Jun-2016)

Ref Expression
Hypotheses ply1ascl.p ⊢ P = Poly 1 ⁡ R
ply1ascl.a ⊢ A = algSc ⁡ P
Assertion ply1ascl ⊢ A = algSc ⁡ 1 𝑜 mPoly R

Proof

Step Hyp Ref Expression
1 ply1ascl.p ⊢ P = Poly 1 ⁡ R
2 ply1ascl.a ⊢ A = algSc ⁡ P
3 eqid ⊢ Scalar ⁡ P = Scalar ⁡ P
4 eqid ⊢ Scalar ⁡ 1 𝑜 mPoly R = Scalar ⁡ 1 𝑜 mPoly R
5 1 ply1sca ⊢ R ∈ V → R = Scalar ⁡ P
6 5 fveq2d ⊢ R ∈ V → Base R = Base Scalar ⁡ P
7 eqid ⊢ 1 𝑜 mPoly R = 1 𝑜 mPoly R
8 1on ⊢ 1 𝑜 ∈ On
9 8 a1i ⊢ R ∈ V → 1 𝑜 ∈ On
10 id ⊢ R ∈ V → R ∈ V
11 7 9 10 mplsca ⊢ R ∈ V → R = Scalar ⁡ 1 𝑜 mPoly R
12 11 fveq2d ⊢ R ∈ V → Base R = Base Scalar ⁡ 1 𝑜 mPoly R
13 eqid ⊢ ⋅ P = ⋅ P
14 1 7 13 ply1vsca ⊢ ⋅ P = ⋅ 1 𝑜 mPoly R
15 14 a1i ⊢ R ∈ V → ⋅ P = ⋅ 1 𝑜 mPoly R
16 15 oveqdr ⊢ R ∈ V ∧ x ∈ Base R ∧ y ∈ V → x ⋅ P y = x ⋅ 1 𝑜 mPoly R y
17 eqid ⊢ 1 P = 1 P
18 7 1 17 ply1mpl1 ⊢ 1 P = 1 1 𝑜 mPoly R
19 18 a1i ⊢ R ∈ V → 1 P = 1 1 𝑜 mPoly R
20 fvexd ⊢ R ∈ V → 1 P ∈ V
21 3 4 6 12 16 19 20 asclpropd ⊢ R ∈ V → algSc ⁡ P = algSc ⁡ 1 𝑜 mPoly R
22 fvprc ⊢ ¬ R ∈ V → Poly 1 ⁡ R = ∅
23 1 22 eqtrid ⊢ ¬ R ∈ V → P = ∅
24 reldmmpl ⊢ Rel ⁡ dom ⁡ mPoly
25 24 ovprc2 ⊢ ¬ R ∈ V → 1 𝑜 mPoly R = ∅
26 23 25 eqtr4d ⊢ ¬ R ∈ V → P = 1 𝑜 mPoly R
27 26 fveq2d ⊢ ¬ R ∈ V → algSc ⁡ P = algSc ⁡ 1 𝑜 mPoly R
28 21 27 pm2.61i ⊢ algSc ⁡ P = algSc ⁡ 1 𝑜 mPoly R
29 2 28 eqtri ⊢ A = algSc ⁡ 1 𝑜 mPoly R