Metamath Proof Explorer


Theorem ply1asclzrhval

Description: Transfer results from algebraic scalars and ZR ring homomorphisms. (Contributed by metakunt, 17-Jun-2025)

Ref Expression
Hypotheses ply1asclzrhval.1 ⊢ W = Poly 1 ⁡ R
ply1asclzrhval.2 ⊢ A = algSc ⁡ W
ply1asclzrhval.3 ⊢ B = ℤRHom ⁡ W
ply1asclzrhval.4 ⊢ C = ℤRHom ⁡ R
ply1asclzrhval.5 ⊢ φ → R ∈ CRing
ply1asclzrhval.6 ⊢ φ → X ∈ ℤ
Assertion ply1asclzrhval ⊢ φ → A ⁡ C ⁡ X = B ⁡ X

Proof

Step Hyp Ref Expression
1 ply1asclzrhval.1 ⊢ W = Poly 1 ⁡ R
2 ply1asclzrhval.2 ⊢ A = algSc ⁡ W
3 ply1asclzrhval.3 ⊢ B = ℤRHom ⁡ W
4 ply1asclzrhval.4 ⊢ C = ℤRHom ⁡ R
5 ply1asclzrhval.5 ⊢ φ → R ∈ CRing
6 ply1asclzrhval.6 ⊢ φ → X ∈ ℤ
7 eqid ⊢ Poly 1 ⁡ R = Poly 1 ⁡ R
8 7 ply1assa ⊢ R ∈ CRing → Poly 1 ⁡ R ∈ AssAlg
9 5 8 syl ⊢ φ → Poly 1 ⁡ R ∈ AssAlg
10 1 9 eqeltrid ⊢ φ → W ∈ AssAlg
11 eqid ⊢ Scalar ⁡ W = Scalar ⁡ W
12 2 11 asclrhm ⊢ W ∈ AssAlg → A ∈ Scalar ⁡ W RingHom W
13 10 12 syl ⊢ φ → A ∈ Scalar ⁡ W RingHom W
14 5 crngringd ⊢ φ → R ∈ Ring
15 1 ply1sca ⊢ R ∈ Ring → R = Scalar ⁡ W
16 14 15 syl ⊢ φ → R = Scalar ⁡ W
17 16 eqcomd ⊢ φ → Scalar ⁡ W = R
18 17 oveq1d ⊢ φ → Scalar ⁡ W RingHom W = R RingHom W
19 13 18 eleqtrd ⊢ φ → A ∈ R RingHom W
20 19 6 4 3 rhmzrhval ⊢ φ → A ⁡ C ⁡ X = B ⁡ X