Metamath Proof Explorer


Theorem psd1

Description: The derivative of one is zero. (Contributed by SN, 25-Apr-2025)

Ref Expression
Hypotheses psd1.s ⊢ S = I mPwSer R
psd1.u ⊢ 1 ˙ = 1 S
psd1.z ⊢ 0 ˙ = 0 S
psd1.i ⊢ φ → I ∈ V
psd1.r ⊢ φ → R ∈ CRing
psd1.x ⊢ φ → X ∈ I
Assertion psd1 ⊢ φ → I mPSDer R ⁡ X ⁡ 1 ˙ = 0 ˙

Proof

Step Hyp Ref Expression
1 psd1.s ⊢ S = I mPwSer R
2 psd1.u ⊢ 1 ˙ = 1 S
3 psd1.z ⊢ 0 ˙ = 0 S
4 psd1.i ⊢ φ → I ∈ V
5 psd1.r ⊢ φ → R ∈ CRing
6 psd1.x ⊢ φ → X ∈ I
7 eqid ⊢ Base S = Base S
8 eqid ⊢ + S = + S
9 eqid ⊢ ⋅ S = ⋅ S
10 1 4 5 psrcrng ⊢ φ → S ∈ CRing
11 10 crngringd ⊢ φ → S ∈ Ring
12 7 2 ringidcl ⊢ S ∈ Ring → 1 ˙ ∈ Base S
13 11 12 syl ⊢ φ → 1 ˙ ∈ Base S
14 1 7 8 9 5 6 13 13 psdmul ⊢ φ → I mPSDer R ⁡ X ⁡ 1 ˙ ⋅ S 1 ˙ = I mPSDer R ⁡ X ⁡ 1 ˙ ⋅ S 1 ˙ + S 1 ˙ ⋅ S I mPSDer R ⁡ X ⁡ 1 ˙
15 7 9 2 11 13 ringlidmd ⊢ φ → 1 ˙ ⋅ S 1 ˙ = 1 ˙
16 15 fveq2d ⊢ φ → I mPSDer R ⁡ X ⁡ 1 ˙ ⋅ S 1 ˙ = I mPSDer R ⁡ X ⁡ 1 ˙
17 5 crnggrpd ⊢ φ → R ∈ Grp
18 17 grpmgmd ⊢ φ → R ∈ Mgm
19 1 7 18 6 13 psdcl ⊢ φ → I mPSDer R ⁡ X ⁡ 1 ˙ ∈ Base S
20 7 9 2 11 19 ringridmd ⊢ φ → I mPSDer R ⁡ X ⁡ 1 ˙ ⋅ S 1 ˙ = I mPSDer R ⁡ X ⁡ 1 ˙
21 7 9 2 11 19 ringlidmd ⊢ φ → 1 ˙ ⋅ S I mPSDer R ⁡ X ⁡ 1 ˙ = I mPSDer R ⁡ X ⁡ 1 ˙
22 20 21 oveq12d ⊢ φ → I mPSDer R ⁡ X ⁡ 1 ˙ ⋅ S 1 ˙ + S 1 ˙ ⋅ S I mPSDer R ⁡ X ⁡ 1 ˙ = I mPSDer R ⁡ X ⁡ 1 ˙ + S I mPSDer R ⁡ X ⁡ 1 ˙
23 14 16 22 3eqtr3rd ⊢ φ → I mPSDer R ⁡ X ⁡ 1 ˙ + S I mPSDer R ⁡ X ⁡ 1 ˙ = I mPSDer R ⁡ X ⁡ 1 ˙
24 10 crnggrpd ⊢ φ → S ∈ Grp
25 7 8 3 grpid ⊢ S ∈ Grp ∧ I mPSDer R ⁡ X ⁡ 1 ˙ ∈ Base S → I mPSDer R ⁡ X ⁡ 1 ˙ + S I mPSDer R ⁡ X ⁡ 1 ˙ = I mPSDer R ⁡ X ⁡ 1 ˙ ↔ 0 ˙ = I mPSDer R ⁡ X ⁡ 1 ˙
26 24 19 25 syl2anc ⊢ φ → I mPSDer R ⁡ X ⁡ 1 ˙ + S I mPSDer R ⁡ X ⁡ 1 ˙ = I mPSDer R ⁡ X ⁡ 1 ˙ ↔ 0 ˙ = I mPSDer R ⁡ X ⁡ 1 ˙
27 23 26 mpbid ⊢ φ → 0 ˙ = I mPSDer R ⁡ X ⁡ 1 ˙
28 27 eqcomd ⊢ φ → I mPSDer R ⁡ X ⁡ 1 ˙ = 0 ˙