Metamath Proof Explorer


Theorem qsxpid

Description: The quotient set of a cartesian product is trivial. (Contributed by Thierry Arnoux, 16-Jan-2024)

Ref Expression
Assertion qsxpid ⊢ A ≠ ∅ → A / A × A = A

Proof

Step Hyp Ref Expression
1 simpr ⊢ x ∈ A ∧ y = x A × A → y = x A × A
2 ecxpid ⊢ x ∈ A → x A × A = A
3 2 adantr ⊢ x ∈ A ∧ y = x A × A → x A × A = A
4 1 3 eqtrd ⊢ x ∈ A ∧ y = x A × A → y = A
5 4 rexlimiva ⊢ ∃ x ∈ A y = x A × A → y = A
6 5 adantl ⊢ A ≠ ∅ ∧ ∃ x ∈ A y = x A × A → y = A
7 n0 ⊢ A ≠ ∅ ↔ ∃ x x ∈ A
8 7 biimpi ⊢ A ≠ ∅ → ∃ x x ∈ A
9 simpl ⊢ y = A ∧ x ∈ A → y = A
10 2 adantl ⊢ y = A ∧ x ∈ A → x A × A = A
11 9 10 eqtr4d ⊢ y = A ∧ x ∈ A → y = x A × A
12 11 ex ⊢ y = A → x ∈ A → y = x A × A
13 12 ancld ⊢ y = A → x ∈ A → x ∈ A ∧ y = x A × A
14 13 eximdv ⊢ y = A → ∃ x x ∈ A → ∃ x x ∈ A ∧ y = x A × A
15 8 14 mpan9 ⊢ A ≠ ∅ ∧ y = A → ∃ x x ∈ A ∧ y = x A × A
16 df-rex ⊢ ∃ x ∈ A y = x A × A ↔ ∃ x x ∈ A ∧ y = x A × A
17 15 16 sylibr ⊢ A ≠ ∅ ∧ y = A → ∃ x ∈ A y = x A × A
18 6 17 impbida ⊢ A ≠ ∅ → ∃ x ∈ A y = x A × A ↔ y = A
19 vex ⊢ y ∈ V
20 19 elqs ⊢ y ∈ A / A × A ↔ ∃ x ∈ A y = x A × A
21 velsn ⊢ y ∈ A ↔ y = A
22 18 20 21 3bitr4g ⊢ A ≠ ∅ → y ∈ A / A × A ↔ y ∈ A
23 22 eqrdv ⊢ A ≠ ∅ → A / A × A = A