Metamath Proof Explorer


Theorem refref

Description: Reflexivity of refinement. (Contributed by Jeff Hankins, 18-Jan-2010)

Ref Expression
Assertion refref ⊢ A ∈ V → A Ref A

Proof

Step Hyp Ref Expression
1 eqid ⊢ ⋃ A = ⋃ A
2 ssid ⊢ x ⊆ x
3 sseq2 ⊢ y = x → x ⊆ y ↔ x ⊆ x
4 3 rspcev ⊢ x ∈ A ∧ x ⊆ x → ∃ y ∈ A x ⊆ y
5 2 4 mpan2 ⊢ x ∈ A → ∃ y ∈ A x ⊆ y
6 5 rgen ⊢ ∀ x ∈ A ∃ y ∈ A x ⊆ y
7 1 6 pm3.2i ⊢ ⋃ A = ⋃ A ∧ ∀ x ∈ A ∃ y ∈ A x ⊆ y
8 1 1 isref ⊢ A ∈ V → A Ref A ↔ ⋃ A = ⋃ A ∧ ∀ x ∈ A ∃ y ∈ A x ⊆ y
9 7 8 mpbiri ⊢ A ∈ V → A Ref A