Metamath Proof Explorer


Theorem signsw0g

Description: The neutral element of W . (Contributed by Thierry Arnoux, 9-Sep-2018)

Ref Expression
Hypotheses signsw.p ⊢ ⨣ ˙ = a ∈ − 1 0 1 , b ∈ − 1 0 1 ⟼ if b = 0 a b
signsw.w ⊢ W = Base ndx − 1 0 1 + ndx ⨣ ˙
Assertion signsw0g ⊢ 0 = 0 W

Proof

Step Hyp Ref Expression
1 signsw.p ⊢ ⨣ ˙ = a ∈ − 1 0 1 , b ∈ − 1 0 1 ⟼ if b = 0 a b
2 signsw.w ⊢ W = Base ndx − 1 0 1 + ndx ⨣ ˙
3 c0ex ⊢ 0 ∈ V
4 3 tpid2 ⊢ 0 ∈ − 1 0 1
5 1 signsw0glem ⊢ ∀ u ∈ − 1 0 1 0 ⨣ ˙ u = u ∧ u ⨣ ˙ 0 = u
6 4 5 pm3.2i ⊢ 0 ∈ − 1 0 1 ∧ ∀ u ∈ − 1 0 1 0 ⨣ ˙ u = u ∧ u ⨣ ˙ 0 = u
7 1 2 signswbase ⊢ − 1 0 1 = Base W
8 eqid ⊢ 0 W = 0 W
9 1 2 signswplusg ⊢ ⨣ ˙ = + W
10 oveq1 ⊢ e = 0 → e ⨣ ˙ u = 0 ⨣ ˙ u
11 10 eqeq1d ⊢ e = 0 → e ⨣ ˙ u = u ↔ 0 ⨣ ˙ u = u
12 11 ovanraleqv ⊢ e = 0 → ∀ u ∈ − 1 0 1 e ⨣ ˙ u = u ∧ u ⨣ ˙ e = u ↔ ∀ u ∈ − 1 0 1 0 ⨣ ˙ u = u ∧ u ⨣ ˙ 0 = u
13 12 rspcev ⊢ 0 ∈ − 1 0 1 ∧ ∀ u ∈ − 1 0 1 0 ⨣ ˙ u = u ∧ u ⨣ ˙ 0 = u → ∃ e ∈ − 1 0 1 ∀ u ∈ − 1 0 1 e ⨣ ˙ u = u ∧ u ⨣ ˙ e = u
14 4 5 13 mp2an ⊢ ∃ e ∈ − 1 0 1 ∀ u ∈ − 1 0 1 e ⨣ ˙ u = u ∧ u ⨣ ˙ e = u
15 14 a1i ⊢ ⊤ → ∃ e ∈ − 1 0 1 ∀ u ∈ − 1 0 1 e ⨣ ˙ u = u ∧ u ⨣ ˙ e = u
16 7 8 9 15 ismgmid ⊢ ⊤ → 0 ∈ − 1 0 1 ∧ ∀ u ∈ − 1 0 1 0 ⨣ ˙ u = u ∧ u ⨣ ˙ 0 = u ↔ 0 W = 0
17 16 mptru ⊢ 0 ∈ − 1 0 1 ∧ ∀ u ∈ − 1 0 1 0 ⨣ ˙ u = u ∧ u ⨣ ˙ 0 = u ↔ 0 W = 0
18 6 17 mpbi ⊢ 0 W = 0
19 18 eqcomi ⊢ 0 = 0 W