Metamath Proof Explorer


Theorem sticksstones14

Description: Sticks and stones with definitions as hypotheses. (Contributed by metakunt, 7-Oct-2024)

Ref Expression
Hypotheses sticksstones14.1 ⊢ φ → N ∈ ℕ 0
sticksstones14.2 ⊢ φ → K ∈ ℕ 0
sticksstones14.3 ⊢ F = a ∈ A ⟼ j ∈ 1 … K ⟼ j + ∑ l = 1 j a ⁡ l
sticksstones14.4 ⊢ G = b ∈ B ⟼ if K = 0 1 N k ∈ 1 … K + 1 ⟼ if k = K + 1 N + K - b ⁡ K if k = 1 b ⁡ 1 − 1 b ⁡ k - b ⁡ k − 1 - 1
sticksstones14.5 ⊢ A = g | g : 1 … K + 1 ⟶ ℕ 0 ∧ ∑ i = 1 K + 1 g ⁡ i = N
sticksstones14.6 ⊢ B = f | f : 1 … K ⟶ 1 … N + K ∧ ∀ x ∈ 1 … K ∀ y ∈ 1 … K x < y → f ⁡ x < f ⁡ y
Assertion sticksstones14 ⊢ φ → A = ( N + K K)

Proof

Step Hyp Ref Expression
1 sticksstones14.1 ⊢ φ → N ∈ ℕ 0
2 sticksstones14.2 ⊢ φ → K ∈ ℕ 0
3 sticksstones14.3 ⊢ F = a ∈ A ⟼ j ∈ 1 … K ⟼ j + ∑ l = 1 j a ⁡ l
4 sticksstones14.4 ⊢ G = b ∈ B ⟼ if K = 0 1 N k ∈ 1 … K + 1 ⟼ if k = K + 1 N + K - b ⁡ K if k = 1 b ⁡ 1 − 1 b ⁡ k - b ⁡ k − 1 - 1
5 sticksstones14.5 ⊢ A = g | g : 1 … K + 1 ⟶ ℕ 0 ∧ ∑ i = 1 K + 1 g ⁡ i = N
6 sticksstones14.6 ⊢ B = f | f : 1 … K ⟶ 1 … N + K ∧ ∀ x ∈ 1 … K ∀ y ∈ 1 … K x < y → f ⁡ x < f ⁡ y
7 5 a1i ⊢ φ → A = g | g : 1 … K + 1 ⟶ ℕ 0 ∧ ∑ i = 1 K + 1 g ⁡ i = N
8 simpl ⊢ g : 1 … K + 1 ⟶ ℕ 0 ∧ ∑ i = 1 K + 1 g ⁡ i = N → g : 1 … K + 1 ⟶ ℕ 0
9 8 a1i ⊢ φ → g : 1 … K + 1 ⟶ ℕ 0 ∧ ∑ i = 1 K + 1 g ⁡ i = N → g : 1 … K + 1 ⟶ ℕ 0
10 9 ss2abdv ⊢ φ → g | g : 1 … K + 1 ⟶ ℕ 0 ∧ ∑ i = 1 K + 1 g ⁡ i = N ⊆ g | g : 1 … K + 1 ⟶ ℕ 0
11 fzfid ⊢ φ → 1 … K + 1 ∈ Fin
12 nn0ex ⊢ ℕ 0 ∈ V
13 12 a1i ⊢ φ → ℕ 0 ∈ V
14 mapex ⊢ 1 … K + 1 ∈ Fin ∧ ℕ 0 ∈ V → g | g : 1 … K + 1 ⟶ ℕ 0 ∈ V
15 11 13 14 syl2anc ⊢ φ → g | g : 1 … K + 1 ⟶ ℕ 0 ∈ V
16 ssexg ⊢ g | g : 1 … K + 1 ⟶ ℕ 0 ∧ ∑ i = 1 K + 1 g ⁡ i = N ⊆ g | g : 1 … K + 1 ⟶ ℕ 0 ∧ g | g : 1 … K + 1 ⟶ ℕ 0 ∈ V → g | g : 1 … K + 1 ⟶ ℕ 0 ∧ ∑ i = 1 K + 1 g ⁡ i = N ∈ V
17 10 15 16 syl2anc ⊢ φ → g | g : 1 … K + 1 ⟶ ℕ 0 ∧ ∑ i = 1 K + 1 g ⁡ i = N ∈ V
18 7 17 eqeltrd ⊢ φ → A ∈ V
19 1 2 3 4 5 6 sticksstones13 ⊢ φ → F : A ⟶ 1-1 onto B
20 18 19 hasheqf1od ⊢ φ → A = B
21 1 2 nn0addcld ⊢ φ → N + K ∈ ℕ 0
22 21 2 6 sticksstones5 ⊢ φ → B = ( N + K K)
23 20 22 eqtrd ⊢ φ → A = ( N + K K)