Metamath Proof Explorer


Theorem subgdisj2

Description: Vectors belonging to disjoint commuting subgroups are uniquely determined by their sum. (Contributed by NM, 12-Jul-2014) (Revised by Mario Carneiro, 19-Apr-2016)

Ref Expression
Hypotheses subgdisj.p ⊢ + ˙ = + G
subgdisj.o ⊢ 0 ˙ = 0 G
subgdisj.z ⊢ Z = Cntz ⁡ G
subgdisj.t ⊢ φ → T ∈ SubGrp ⁡ G
subgdisj.u ⊢ φ → U ∈ SubGrp ⁡ G
subgdisj.i ⊢ φ → T ∩ U = 0 ˙
subgdisj.s ⊢ φ → T ⊆ Z ⁡ U
subgdisj.a ⊢ φ → A ∈ T
subgdisj.c ⊢ φ → C ∈ T
subgdisj.b ⊢ φ → B ∈ U
subgdisj.d ⊢ φ → D ∈ U
subgdisj.j ⊢ φ → A + ˙ B = C + ˙ D
Assertion subgdisj2 ⊢ φ → B = D

Proof

Step Hyp Ref Expression
1 subgdisj.p ⊢ + ˙ = + G
2 subgdisj.o ⊢ 0 ˙ = 0 G
3 subgdisj.z ⊢ Z = Cntz ⁡ G
4 subgdisj.t ⊢ φ → T ∈ SubGrp ⁡ G
5 subgdisj.u ⊢ φ → U ∈ SubGrp ⁡ G
6 subgdisj.i ⊢ φ → T ∩ U = 0 ˙
7 subgdisj.s ⊢ φ → T ⊆ Z ⁡ U
8 subgdisj.a ⊢ φ → A ∈ T
9 subgdisj.c ⊢ φ → C ∈ T
10 subgdisj.b ⊢ φ → B ∈ U
11 subgdisj.d ⊢ φ → D ∈ U
12 subgdisj.j ⊢ φ → A + ˙ B = C + ˙ D
13 incom ⊢ T ∩ U = U ∩ T
14 13 6 eqtr3id ⊢ φ → U ∩ T = 0 ˙
15 3 4 5 7 cntzrecd ⊢ φ → U ⊆ Z ⁡ T
16 7 8 sseldd ⊢ φ → A ∈ Z ⁡ U
17 1 3 cntzi ⊢ A ∈ Z ⁡ U ∧ B ∈ U → A + ˙ B = B + ˙ A
18 16 10 17 syl2anc ⊢ φ → A + ˙ B = B + ˙ A
19 7 9 sseldd ⊢ φ → C ∈ Z ⁡ U
20 1 3 cntzi ⊢ C ∈ Z ⁡ U ∧ D ∈ U → C + ˙ D = D + ˙ C
21 19 11 20 syl2anc ⊢ φ → C + ˙ D = D + ˙ C
22 12 18 21 3eqtr3d ⊢ φ → B + ˙ A = D + ˙ C
23 1 2 3 5 4 14 15 10 11 8 9 22 subgdisj1 ⊢ φ → B = D