Metamath Proof Explorer


Theorem tposfn2

Description: The domain of a transposition. (Contributed by NM, 10-Sep-2015)

Ref Expression
Assertion tposfn2 ⊢ Rel ⁡ A → F Fn A → tpos F Fn A -1

Proof

Step Hyp Ref Expression
1 tposfun ⊢ Fun ⁡ F → Fun ⁡ tpos F
2 1 a1i ⊢ Rel ⁡ A → Fun ⁡ F → Fun ⁡ tpos F
3 dmtpos ⊢ Rel ⁡ dom ⁡ F → dom ⁡ tpos F = dom ⁡ F -1
4 3 a1i ⊢ dom ⁡ F = A → Rel ⁡ dom ⁡ F → dom ⁡ tpos F = dom ⁡ F -1
5 releq ⊢ dom ⁡ F = A → Rel ⁡ dom ⁡ F ↔ Rel ⁡ A
6 cnveq ⊢ dom ⁡ F = A → dom ⁡ F -1 = A -1
7 6 eqeq2d ⊢ dom ⁡ F = A → dom ⁡ tpos F = dom ⁡ F -1 ↔ dom ⁡ tpos F = A -1
8 4 5 7 3imtr3d ⊢ dom ⁡ F = A → Rel ⁡ A → dom ⁡ tpos F = A -1
9 8 com12 ⊢ Rel ⁡ A → dom ⁡ F = A → dom ⁡ tpos F = A -1
10 2 9 anim12d ⊢ Rel ⁡ A → Fun ⁡ F ∧ dom ⁡ F = A → Fun ⁡ tpos F ∧ dom ⁡ tpos F = A -1
11 df-fn ⊢ F Fn A ↔ Fun ⁡ F ∧ dom ⁡ F = A
12 df-fn ⊢ tpos F Fn A -1 ↔ Fun ⁡ tpos F ∧ dom ⁡ tpos F = A -1
13 10 11 12 3imtr4g ⊢ Rel ⁡ A → F Fn A → tpos F Fn A -1