Metamath Proof Explorer


Theorem trrelsuperrel2dg

Description: Concrete construction of a superclass of relation R which is a transitive relation. (Contributed by RP, 20-Jul-2020)

Ref Expression
Hypothesis trrelsuperrel2dg.s ⊢ φ → S = R ∪ dom ⁡ R × ran ⁡ R
Assertion trrelsuperrel2dg ⊢ φ → R ⊆ S ∧ S ∘ S ⊆ S

Proof

Step Hyp Ref Expression
1 trrelsuperrel2dg.s ⊢ φ → S = R ∪ dom ⁡ R × ran ⁡ R
2 ssun1 ⊢ R ⊆ R ∪ dom ⁡ R × ran ⁡ R
3 2 1 sseqtrrid ⊢ φ → R ⊆ S
4 xptrrel ⊢ dom ⁡ R × ran ⁡ R ∘ dom ⁡ R × ran ⁡ R ⊆ dom ⁡ R × ran ⁡ R
5 ssun2 ⊢ dom ⁡ R × ran ⁡ R ⊆ R ∪ dom ⁡ R × ran ⁡ R
6 4 5 sstri ⊢ dom ⁡ R × ran ⁡ R ∘ dom ⁡ R × ran ⁡ R ⊆ R ∪ dom ⁡ R × ran ⁡ R
7 6 a1i ⊢ φ → dom ⁡ R × ran ⁡ R ∘ dom ⁡ R × ran ⁡ R ⊆ R ∪ dom ⁡ R × ran ⁡ R
8 1 1 coeq12d ⊢ φ → S ∘ S = R ∪ dom ⁡ R × ran ⁡ R ∘ R ∪ dom ⁡ R × ran ⁡ R
9 coundir ⊢ R ∪ dom ⁡ R × ran ⁡ R ∘ R ∪ dom ⁡ R × ran ⁡ R = R ∘ R ∪ dom ⁡ R × ran ⁡ R ∪ dom ⁡ R × ran ⁡ R ∘ R ∪ dom ⁡ R × ran ⁡ R
10 relcnv ⊢ Rel ⁡ R -1 -1
11 cocnvcnv1 ⊢ R -1 -1 ∘ R ∪ dom ⁡ R × ran ⁡ R = R ∘ R ∪ dom ⁡ R × ran ⁡ R
12 relssdmrn ⊢ Rel ⁡ R -1 -1 → R -1 -1 ⊆ dom ⁡ R -1 -1 × ran ⁡ R -1 -1
13 dmcnvcnv ⊢ dom ⁡ R -1 -1 = dom ⁡ R
14 rncnvcnv ⊢ ran ⁡ R -1 -1 = ran ⁡ R
15 13 14 xpeq12i ⊢ dom ⁡ R -1 -1 × ran ⁡ R -1 -1 = dom ⁡ R × ran ⁡ R
16 12 15 sseqtrdi ⊢ Rel ⁡ R -1 -1 → R -1 -1 ⊆ dom ⁡ R × ran ⁡ R
17 coss1 ⊢ R -1 -1 ⊆ dom ⁡ R × ran ⁡ R → R -1 -1 ∘ R ∪ dom ⁡ R × ran ⁡ R ⊆ dom ⁡ R × ran ⁡ R ∘ R ∪ dom ⁡ R × ran ⁡ R
18 16 17 syl ⊢ Rel ⁡ R -1 -1 → R -1 -1 ∘ R ∪ dom ⁡ R × ran ⁡ R ⊆ dom ⁡ R × ran ⁡ R ∘ R ∪ dom ⁡ R × ran ⁡ R
19 11 18 eqsstrrid ⊢ Rel ⁡ R -1 -1 → R ∘ R ∪ dom ⁡ R × ran ⁡ R ⊆ dom ⁡ R × ran ⁡ R ∘ R ∪ dom ⁡ R × ran ⁡ R
20 ssequn1 ⊢ R ∘ R ∪ dom ⁡ R × ran ⁡ R ⊆ dom ⁡ R × ran ⁡ R ∘ R ∪ dom ⁡ R × ran ⁡ R ↔ R ∘ R ∪ dom ⁡ R × ran ⁡ R ∪ dom ⁡ R × ran ⁡ R ∘ R ∪ dom ⁡ R × ran ⁡ R = dom ⁡ R × ran ⁡ R ∘ R ∪ dom ⁡ R × ran ⁡ R
21 19 20 sylib ⊢ Rel ⁡ R -1 -1 → R ∘ R ∪ dom ⁡ R × ran ⁡ R ∪ dom ⁡ R × ran ⁡ R ∘ R ∪ dom ⁡ R × ran ⁡ R = dom ⁡ R × ran ⁡ R ∘ R ∪ dom ⁡ R × ran ⁡ R
22 10 21 ax-mp ⊢ R ∘ R ∪ dom ⁡ R × ran ⁡ R ∪ dom ⁡ R × ran ⁡ R ∘ R ∪ dom ⁡ R × ran ⁡ R = dom ⁡ R × ran ⁡ R ∘ R ∪ dom ⁡ R × ran ⁡ R
23 9 22 eqtri ⊢ R ∪ dom ⁡ R × ran ⁡ R ∘ R ∪ dom ⁡ R × ran ⁡ R = dom ⁡ R × ran ⁡ R ∘ R ∪ dom ⁡ R × ran ⁡ R
24 coundi ⊢ dom ⁡ R × ran ⁡ R ∘ R ∪ dom ⁡ R × ran ⁡ R = dom ⁡ R × ran ⁡ R ∘ R ∪ dom ⁡ R × ran ⁡ R ∘ dom ⁡ R × ran ⁡ R
25 cocnvcnv2 ⊢ dom ⁡ R × ran ⁡ R ∘ R -1 -1 = dom ⁡ R × ran ⁡ R ∘ R
26 coss2 ⊢ R -1 -1 ⊆ dom ⁡ R × ran ⁡ R → dom ⁡ R × ran ⁡ R ∘ R -1 -1 ⊆ dom ⁡ R × ran ⁡ R ∘ dom ⁡ R × ran ⁡ R
27 16 26 syl ⊢ Rel ⁡ R -1 -1 → dom ⁡ R × ran ⁡ R ∘ R -1 -1 ⊆ dom ⁡ R × ran ⁡ R ∘ dom ⁡ R × ran ⁡ R
28 25 27 eqsstrrid ⊢ Rel ⁡ R -1 -1 → dom ⁡ R × ran ⁡ R ∘ R ⊆ dom ⁡ R × ran ⁡ R ∘ dom ⁡ R × ran ⁡ R
29 ssequn1 ⊢ dom ⁡ R × ran ⁡ R ∘ R ⊆ dom ⁡ R × ran ⁡ R ∘ dom ⁡ R × ran ⁡ R ↔ dom ⁡ R × ran ⁡ R ∘ R ∪ dom ⁡ R × ran ⁡ R ∘ dom ⁡ R × ran ⁡ R = dom ⁡ R × ran ⁡ R ∘ dom ⁡ R × ran ⁡ R
30 28 29 sylib ⊢ Rel ⁡ R -1 -1 → dom ⁡ R × ran ⁡ R ∘ R ∪ dom ⁡ R × ran ⁡ R ∘ dom ⁡ R × ran ⁡ R = dom ⁡ R × ran ⁡ R ∘ dom ⁡ R × ran ⁡ R
31 10 30 ax-mp ⊢ dom ⁡ R × ran ⁡ R ∘ R ∪ dom ⁡ R × ran ⁡ R ∘ dom ⁡ R × ran ⁡ R = dom ⁡ R × ran ⁡ R ∘ dom ⁡ R × ran ⁡ R
32 24 31 eqtri ⊢ dom ⁡ R × ran ⁡ R ∘ R ∪ dom ⁡ R × ran ⁡ R = dom ⁡ R × ran ⁡ R ∘ dom ⁡ R × ran ⁡ R
33 23 32 eqtri ⊢ R ∪ dom ⁡ R × ran ⁡ R ∘ R ∪ dom ⁡ R × ran ⁡ R = dom ⁡ R × ran ⁡ R ∘ dom ⁡ R × ran ⁡ R
34 8 33 eqtrdi ⊢ φ → S ∘ S = dom ⁡ R × ran ⁡ R ∘ dom ⁡ R × ran ⁡ R
35 7 34 1 3sstr4d ⊢ φ → S ∘ S ⊆ S
36 3 35 jca ⊢ φ → R ⊆ S ∧ S ∘ S ⊆ S