Metamath Proof Explorer


Theorem vonhoi

Description: The Lebesgue outer measure of a multidimensional half-open interval is its dimensional volume (the product of its length in each dimension, when the dimension is nonzero). A direct consequence of Proposition 115D (b) of Fremlin1 p. 30. (Contributed by Glauco Siliprandi, 8-Apr-2021)

Ref Expression
Hypotheses vonhoi.x ⊢ φ → X ∈ Fin
vonhoi.a ⊢ φ → A : X ⟶ ℝ
vonhoi.b ⊢ φ → B : X ⟶ ℝ
vonhoi.c ⊢ I = ⨉ k ∈ X A ⁡ k B ⁡ k
vonhoi.l ⊢ L = x ∈ Fin ⟼ a ∈ ℝ x , b ∈ ℝ x ⟼ if x = ∅ 0 ∏ k ∈ x vol ⁡ a ⁡ k b ⁡ k
Assertion vonhoi ⊢ φ → voln ⁡ X ⁡ I = A L ⁡ X B

Proof

Step Hyp Ref Expression
1 vonhoi.x ⊢ φ → X ∈ Fin
2 vonhoi.a ⊢ φ → A : X ⟶ ℝ
3 vonhoi.b ⊢ φ → B : X ⟶ ℝ
4 vonhoi.c ⊢ I = ⨉ k ∈ X A ⁡ k B ⁡ k
5 vonhoi.l ⊢ L = x ∈ Fin ⟼ a ∈ ℝ x , b ∈ ℝ x ⟼ if x = ∅ 0 ∏ k ∈ x vol ⁡ a ⁡ k b ⁡ k
6 eqid ⊢ dom ⁡ voln ⁡ X = dom ⁡ voln ⁡ X
7 1 6 2 3 hoimbl ⊢ φ → ⨉ k ∈ X A ⁡ k B ⁡ k ∈ dom ⁡ voln ⁡ X
8 4 7 eqeltrid ⊢ φ → I ∈ dom ⁡ voln ⁡ X
9 1 8 mblvon ⊢ φ → voln ⁡ X ⁡ I = voln* ⁡ X ⁡ I
10 1 2 3 4 5 ovnhoi ⊢ φ → voln* ⁡ X ⁡ I = A L ⁡ X B
11 9 10 eqtrd ⊢ φ → voln ⁡ X ⁡ I = A L ⁡ X B