Metamath Proof Explorer


Theorem vtoclgft

Description: Closed theorem form of vtoclgf . The reverse implication is proven in ceqsal1t . See ceqsalt for a version with x and A disjoint. (Contributed by NM, 17-Feb-2013) (Revised by Mario Carneiro, 12-Oct-2016) (Proof shortened by JJ, 11-Aug-2021) Avoid ax-13 . (Revised by GG, 6-Oct-2023)

Ref Expression
Assertion vtoclgft ⊢ Ⅎ _ x A ∧ Ⅎ x ψ ∧ ∀ x x = A → φ ↔ ψ ∧ ∀ x φ ∧ A ∈ V → ψ

Proof

Step Hyp Ref Expression
1 biimp ⊢ φ ↔ ψ → φ → ψ
2 1 imim2i ⊢ x = A → φ ↔ ψ → x = A → φ → ψ
3 2 alimi ⊢ ∀ x x = A → φ ↔ ψ → ∀ x x = A → φ → ψ
4 spcimgft ⊢ Ⅎ _ x A ∧ Ⅎ x ψ ∧ ∀ x x = A → φ → ψ → A ∈ V → ∀ x φ → ψ
5 3 4 sylan2 ⊢ Ⅎ _ x A ∧ Ⅎ x ψ ∧ ∀ x x = A → φ ↔ ψ → A ∈ V → ∀ x φ → ψ
6 5 com23 ⊢ Ⅎ _ x A ∧ Ⅎ x ψ ∧ ∀ x x = A → φ ↔ ψ → ∀ x φ → A ∈ V → ψ
7 6 impr ⊢ Ⅎ _ x A ∧ Ⅎ x ψ ∧ ∀ x x = A → φ ↔ ψ ∧ ∀ x φ → A ∈ V → ψ
8 7 3impia ⊢ Ⅎ _ x A ∧ Ⅎ x ψ ∧ ∀ x x = A → φ ↔ ψ ∧ ∀ x φ ∧ A ∈ V → ψ