Metamath Proof Explorer


Theorem zaddscl

Description: The surreal integers are closed under addition. (Contributed by Scott Fenton, 25-Jul-2025)

Ref Expression
Assertion zaddscl ⊢ A ∈ ℤ s ∧ B ∈ ℤ s → A + s B ∈ ℤ s

Proof

Step Hyp Ref Expression
1 reeanv ⊢ ∃ x ∈ ℕ s ∃ z ∈ ℕ s ∃ y ∈ ℕ s A = x - s y ∧ ∃ w ∈ ℕ s B = z - s w ↔ ∃ x ∈ ℕ s ∃ y ∈ ℕ s A = x - s y ∧ ∃ z ∈ ℕ s ∃ w ∈ ℕ s B = z - s w
2 reeanv ⊢ ∃ y ∈ ℕ s ∃ w ∈ ℕ s A = x - s y ∧ B = z - s w ↔ ∃ y ∈ ℕ s A = x - s y ∧ ∃ w ∈ ℕ s B = z - s w
3 2 2rexbii ⊢ ∃ x ∈ ℕ s ∃ z ∈ ℕ s ∃ y ∈ ℕ s ∃ w ∈ ℕ s A = x - s y ∧ B = z - s w ↔ ∃ x ∈ ℕ s ∃ z ∈ ℕ s ∃ y ∈ ℕ s A = x - s y ∧ ∃ w ∈ ℕ s B = z - s w
4 elzs ⊢ A ∈ ℤ s ↔ ∃ x ∈ ℕ s ∃ y ∈ ℕ s A = x - s y
5 elzs ⊢ B ∈ ℤ s ↔ ∃ z ∈ ℕ s ∃ w ∈ ℕ s B = z - s w
6 4 5 anbi12i ⊢ A ∈ ℤ s ∧ B ∈ ℤ s ↔ ∃ x ∈ ℕ s ∃ y ∈ ℕ s A = x - s y ∧ ∃ z ∈ ℕ s ∃ w ∈ ℕ s B = z - s w
7 1 3 6 3bitr4ri ⊢ A ∈ ℤ s ∧ B ∈ ℤ s ↔ ∃ x ∈ ℕ s ∃ z ∈ ℕ s ∃ y ∈ ℕ s ∃ w ∈ ℕ s A = x - s y ∧ B = z - s w
8 simpll ⊢ x ∈ ℕ s ∧ z ∈ ℕ s ∧ y ∈ ℕ s ∧ w ∈ ℕ s → x ∈ ℕ s
9 8 nnnod ⊢ x ∈ ℕ s ∧ z ∈ ℕ s ∧ y ∈ ℕ s ∧ w ∈ ℕ s → x ∈ No
10 simplr ⊢ x ∈ ℕ s ∧ z ∈ ℕ s ∧ y ∈ ℕ s ∧ w ∈ ℕ s → z ∈ ℕ s
11 10 nnnod ⊢ x ∈ ℕ s ∧ z ∈ ℕ s ∧ y ∈ ℕ s ∧ w ∈ ℕ s → z ∈ No
12 simprl ⊢ x ∈ ℕ s ∧ z ∈ ℕ s ∧ y ∈ ℕ s ∧ w ∈ ℕ s → y ∈ ℕ s
13 12 nnnod ⊢ x ∈ ℕ s ∧ z ∈ ℕ s ∧ y ∈ ℕ s ∧ w ∈ ℕ s → y ∈ No
14 simprr ⊢ x ∈ ℕ s ∧ z ∈ ℕ s ∧ y ∈ ℕ s ∧ w ∈ ℕ s → w ∈ ℕ s
15 14 nnnod ⊢ x ∈ ℕ s ∧ z ∈ ℕ s ∧ y ∈ ℕ s ∧ w ∈ ℕ s → w ∈ No
16 9 11 13 15 addsubs4d ⊢ x ∈ ℕ s ∧ z ∈ ℕ s ∧ y ∈ ℕ s ∧ w ∈ ℕ s → x + s z - s y + s w = x - s y + s z - s w
17 nnaddscl ⊢ x ∈ ℕ s ∧ z ∈ ℕ s → x + s z ∈ ℕ s
18 nnaddscl ⊢ y ∈ ℕ s ∧ w ∈ ℕ s → y + s w ∈ ℕ s
19 nnzsubs ⊢ x + s z ∈ ℕ s ∧ y + s w ∈ ℕ s → x + s z - s y + s w ∈ ℤ s
20 17 18 19 syl2an ⊢ x ∈ ℕ s ∧ z ∈ ℕ s ∧ y ∈ ℕ s ∧ w ∈ ℕ s → x + s z - s y + s w ∈ ℤ s
21 16 20 eqeltrrd ⊢ x ∈ ℕ s ∧ z ∈ ℕ s ∧ y ∈ ℕ s ∧ w ∈ ℕ s → x - s y + s z - s w ∈ ℤ s
22 oveq12 ⊢ A = x - s y ∧ B = z - s w → A + s B = x - s y + s z - s w
23 22 eleq1d ⊢ A = x - s y ∧ B = z - s w → A + s B ∈ ℤ s ↔ x - s y + s z - s w ∈ ℤ s
24 21 23 syl5ibrcom ⊢ x ∈ ℕ s ∧ z ∈ ℕ s ∧ y ∈ ℕ s ∧ w ∈ ℕ s → A = x - s y ∧ B = z - s w → A + s B ∈ ℤ s
25 24 rexlimdvva ⊢ x ∈ ℕ s ∧ z ∈ ℕ s → ∃ y ∈ ℕ s ∃ w ∈ ℕ s A = x - s y ∧ B = z - s w → A + s B ∈ ℤ s
26 25 rexlimivv ⊢ ∃ x ∈ ℕ s ∃ z ∈ ℕ s ∃ y ∈ ℕ s ∃ w ∈ ℕ s A = x - s y ∧ B = z - s w → A + s B ∈ ℤ s
27 7 26 sylbi ⊢ A ∈ ℤ s ∧ B ∈ ℤ s → A + s B ∈ ℤ s