Metamath Proof Explorer


Theorem ablsimpnosubgd

Description: A subgroup of an abelian simple group containing a nonidentity element is the whole group. (Contributed by Rohan Ridenour, 3-Aug-2023)

Ref Expression
Hypotheses ablsimpnosubgd.1 ⊢ 𝐵 = ( Base ‘ 𝐺 )
ablsimpnosubgd.2 ⊢ 0 = ( 0g ‘ 𝐺 )
ablsimpnosubgd.3 ⊢ ( 𝜑 → 𝐺 ∈ Abel )
ablsimpnosubgd.4 ⊢ ( 𝜑 → 𝐺 ∈ SimpGrp )
ablsimpnosubgd.5 ⊢ ( 𝜑 → 𝑆 ∈ ( SubGrp ‘ 𝐺 ) )
ablsimpnosubgd.6 ⊢ ( 𝜑 → 𝐴 ∈ 𝑆 )
ablsimpnosubgd.7 ⊢ ( 𝜑 → ¬ 𝐴 = 0 )
Assertion ablsimpnosubgd ( 𝜑 → 𝑆 = 𝐵 )

Proof

Step Hyp Ref Expression
1 ablsimpnosubgd.1 ⊢ 𝐵 = ( Base ‘ 𝐺 )
2 ablsimpnosubgd.2 ⊢ 0 = ( 0g ‘ 𝐺 )
3 ablsimpnosubgd.3 ⊢ ( 𝜑 → 𝐺 ∈ Abel )
4 ablsimpnosubgd.4 ⊢ ( 𝜑 → 𝐺 ∈ SimpGrp )
5 ablsimpnosubgd.5 ⊢ ( 𝜑 → 𝑆 ∈ ( SubGrp ‘ 𝐺 ) )
6 ablsimpnosubgd.6 ⊢ ( 𝜑 → 𝐴 ∈ 𝑆 )
7 ablsimpnosubgd.7 ⊢ ( 𝜑 → ¬ 𝐴 = 0 )
8 elsni ⊢ ( 𝐴 ∈ { 0 } → 𝐴 = 0 )
9 7 8 nsyl ⊢ ( 𝜑 → ¬ 𝐴 ∈ { 0 } )
10 eleq2 ⊢ ( 𝑆 = { 0 } → ( 𝐴 ∈ 𝑆 ↔ 𝐴 ∈ { 0 } ) )
11 6 10 syl5ibcom ⊢ ( 𝜑 → ( 𝑆 = { 0 } → 𝐴 ∈ { 0 } ) )
12 9 11 mtod ⊢ ( 𝜑 → ¬ 𝑆 = { 0 } )
13 12 pm2.21d ⊢ ( 𝜑 → ( 𝑆 = { 0 } → 𝑆 = 𝐵 ) )
14 idd ⊢ ( 𝜑 → ( 𝑆 = 𝐵 → 𝑆 = 𝐵 ) )
15 ablnsg ⊢ ( 𝐺 ∈ Abel → ( NrmSGrp ‘ 𝐺 ) = ( SubGrp ‘ 𝐺 ) )
16 15 eqcomd ⊢ ( 𝐺 ∈ Abel → ( SubGrp ‘ 𝐺 ) = ( NrmSGrp ‘ 𝐺 ) )
17 3 16 syl ⊢ ( 𝜑 → ( SubGrp ‘ 𝐺 ) = ( NrmSGrp ‘ 𝐺 ) )
18 5 17 eleqtrd ⊢ ( 𝜑 → 𝑆 ∈ ( NrmSGrp ‘ 𝐺 ) )
19 1 2 4 18 simpgnsgeqd ⊢ ( 𝜑 → ( 𝑆 = { 0 } ∨ 𝑆 = 𝐵 ) )
20 13 14 19 mpjaod ⊢ ( 𝜑 → 𝑆 = 𝐵 )