Metamath Proof Explorer


Theorem addscan2

Description: Cancellation law for surreal addition. (Contributed by Scott Fenton, 21-Jan-2025)

Ref Expression
Assertion addscan2 ( ( 𝐴 ∈ No ∧ 𝐵 ∈ No ∧ 𝐶 ∈ No ) → ( ( 𝐴 +s 𝐶 ) = ( 𝐵 +s 𝐶 ) ↔ 𝐴 = 𝐵 ) )

Proof

Step Hyp Ref Expression
1 leadds1 ⊢ ( ( 𝐴 ∈ No ∧ 𝐵 ∈ No ∧ 𝐶 ∈ No ) → ( 𝐴 ≤s 𝐵 ↔ ( 𝐴 +s 𝐶 ) ≤s ( 𝐵 +s 𝐶 ) ) )
2 leadds1 ⊢ ( ( 𝐵 ∈ No ∧ 𝐴 ∈ No ∧ 𝐶 ∈ No ) → ( 𝐵 ≤s 𝐴 ↔ ( 𝐵 +s 𝐶 ) ≤s ( 𝐴 +s 𝐶 ) ) )
3 2 3com12 ⊢ ( ( 𝐴 ∈ No ∧ 𝐵 ∈ No ∧ 𝐶 ∈ No ) → ( 𝐵 ≤s 𝐴 ↔ ( 𝐵 +s 𝐶 ) ≤s ( 𝐴 +s 𝐶 ) ) )
4 1 3 anbi12d ⊢ ( ( 𝐴 ∈ No ∧ 𝐵 ∈ No ∧ 𝐶 ∈ No ) → ( ( 𝐴 ≤s 𝐵 ∧ 𝐵 ≤s 𝐴 ) ↔ ( ( 𝐴 +s 𝐶 ) ≤s ( 𝐵 +s 𝐶 ) ∧ ( 𝐵 +s 𝐶 ) ≤s ( 𝐴 +s 𝐶 ) ) ) )
5 lestri3 ⊢ ( ( 𝐴 ∈ No ∧ 𝐵 ∈ No ) → ( 𝐴 = 𝐵 ↔ ( 𝐴 ≤s 𝐵 ∧ 𝐵 ≤s 𝐴 ) ) )
6 5 3adant3 ⊢ ( ( 𝐴 ∈ No ∧ 𝐵 ∈ No ∧ 𝐶 ∈ No ) → ( 𝐴 = 𝐵 ↔ ( 𝐴 ≤s 𝐵 ∧ 𝐵 ≤s 𝐴 ) ) )
7 addscl ⊢ ( ( 𝐴 ∈ No ∧ 𝐶 ∈ No ) → ( 𝐴 +s 𝐶 ) ∈ No )
8 7 3adant2 ⊢ ( ( 𝐴 ∈ No ∧ 𝐵 ∈ No ∧ 𝐶 ∈ No ) → ( 𝐴 +s 𝐶 ) ∈ No )
9 addscl ⊢ ( ( 𝐵 ∈ No ∧ 𝐶 ∈ No ) → ( 𝐵 +s 𝐶 ) ∈ No )
10 9 3adant1 ⊢ ( ( 𝐴 ∈ No ∧ 𝐵 ∈ No ∧ 𝐶 ∈ No ) → ( 𝐵 +s 𝐶 ) ∈ No )
11 lestri3 ⊢ ( ( ( 𝐴 +s 𝐶 ) ∈ No ∧ ( 𝐵 +s 𝐶 ) ∈ No ) → ( ( 𝐴 +s 𝐶 ) = ( 𝐵 +s 𝐶 ) ↔ ( ( 𝐴 +s 𝐶 ) ≤s ( 𝐵 +s 𝐶 ) ∧ ( 𝐵 +s 𝐶 ) ≤s ( 𝐴 +s 𝐶 ) ) ) )
12 8 10 11 syl2anc ⊢ ( ( 𝐴 ∈ No ∧ 𝐵 ∈ No ∧ 𝐶 ∈ No ) → ( ( 𝐴 +s 𝐶 ) = ( 𝐵 +s 𝐶 ) ↔ ( ( 𝐴 +s 𝐶 ) ≤s ( 𝐵 +s 𝐶 ) ∧ ( 𝐵 +s 𝐶 ) ≤s ( 𝐴 +s 𝐶 ) ) ) )
13 4 6 12 3bitr4rd ⊢ ( ( 𝐴 ∈ No ∧ 𝐵 ∈ No ∧ 𝐶 ∈ No ) → ( ( 𝐴 +s 𝐶 ) = ( 𝐵 +s 𝐶 ) ↔ 𝐴 = 𝐵 ) )