Metamath Proof Explorer


Theorem eulplig

Description: Through two distinct points of a planar incidence geometry, there is a unique line. (Contributed by BJ, 2-Dec-2021)

Ref Expression
Hypothesis eulplig.1 ⊢ 𝑃 = ∪ 𝐺
Assertion eulplig ( ( 𝐺 ∈ Plig ∧ ( ( 𝐴 ∈ 𝑃 ∧ 𝐵 ∈ 𝑃 ) ∧ 𝐴 ≠ 𝐵 ) ) → ∃! 𝑙 ∈ 𝐺 ( 𝐴 ∈ 𝑙 ∧ 𝐵 ∈ 𝑙 ) )

Proof

Step Hyp Ref Expression
1 eulplig.1 ⊢ 𝑃 = ∪ 𝐺
2 1 isplig ⊢ ( 𝐺 ∈ Plig → ( 𝐺 ∈ Plig ↔ ( ∀ 𝑎 ∈ 𝑃 ∀ 𝑏 ∈ 𝑃 ( 𝑎 ≠ 𝑏 → ∃! 𝑙 ∈ 𝐺 ( 𝑎 ∈ 𝑙 ∧ 𝑏 ∈ 𝑙 ) ) ∧ ∀ 𝑙 ∈ 𝐺 ∃ 𝑎 ∈ 𝑃 ∃ 𝑏 ∈ 𝑃 ( 𝑎 ≠ 𝑏 ∧ 𝑎 ∈ 𝑙 ∧ 𝑏 ∈ 𝑙 ) ∧ ∃ 𝑎 ∈ 𝑃 ∃ 𝑏 ∈ 𝑃 ∃ 𝑐 ∈ 𝑃 ∀ 𝑙 ∈ 𝐺 ¬ ( 𝑎 ∈ 𝑙 ∧ 𝑏 ∈ 𝑙 ∧ 𝑐 ∈ 𝑙 ) ) ) )
3 2 ibi ⊢ ( 𝐺 ∈ Plig → ( ∀ 𝑎 ∈ 𝑃 ∀ 𝑏 ∈ 𝑃 ( 𝑎 ≠ 𝑏 → ∃! 𝑙 ∈ 𝐺 ( 𝑎 ∈ 𝑙 ∧ 𝑏 ∈ 𝑙 ) ) ∧ ∀ 𝑙 ∈ 𝐺 ∃ 𝑎 ∈ 𝑃 ∃ 𝑏 ∈ 𝑃 ( 𝑎 ≠ 𝑏 ∧ 𝑎 ∈ 𝑙 ∧ 𝑏 ∈ 𝑙 ) ∧ ∃ 𝑎 ∈ 𝑃 ∃ 𝑏 ∈ 𝑃 ∃ 𝑐 ∈ 𝑃 ∀ 𝑙 ∈ 𝐺 ¬ ( 𝑎 ∈ 𝑙 ∧ 𝑏 ∈ 𝑙 ∧ 𝑐 ∈ 𝑙 ) ) )
4 simp1 ⊢ ( ( ∀ 𝑎 ∈ 𝑃 ∀ 𝑏 ∈ 𝑃 ( 𝑎 ≠ 𝑏 → ∃! 𝑙 ∈ 𝐺 ( 𝑎 ∈ 𝑙 ∧ 𝑏 ∈ 𝑙 ) ) ∧ ∀ 𝑙 ∈ 𝐺 ∃ 𝑎 ∈ 𝑃 ∃ 𝑏 ∈ 𝑃 ( 𝑎 ≠ 𝑏 ∧ 𝑎 ∈ 𝑙 ∧ 𝑏 ∈ 𝑙 ) ∧ ∃ 𝑎 ∈ 𝑃 ∃ 𝑏 ∈ 𝑃 ∃ 𝑐 ∈ 𝑃 ∀ 𝑙 ∈ 𝐺 ¬ ( 𝑎 ∈ 𝑙 ∧ 𝑏 ∈ 𝑙 ∧ 𝑐 ∈ 𝑙 ) ) → ∀ 𝑎 ∈ 𝑃 ∀ 𝑏 ∈ 𝑃 ( 𝑎 ≠ 𝑏 → ∃! 𝑙 ∈ 𝐺 ( 𝑎 ∈ 𝑙 ∧ 𝑏 ∈ 𝑙 ) ) )
5 simpl ⊢ ( ( 𝑎 = 𝐴 ∧ 𝑏 = 𝐵 ) → 𝑎 = 𝐴 )
6 simpr ⊢ ( ( 𝑎 = 𝐴 ∧ 𝑏 = 𝐵 ) → 𝑏 = 𝐵 )
7 5 6 neeq12d ⊢ ( ( 𝑎 = 𝐴 ∧ 𝑏 = 𝐵 ) → ( 𝑎 ≠ 𝑏 ↔ 𝐴 ≠ 𝐵 ) )
8 eleq1 ⊢ ( 𝑎 = 𝐴 → ( 𝑎 ∈ 𝑙 ↔ 𝐴 ∈ 𝑙 ) )
9 eleq1 ⊢ ( 𝑏 = 𝐵 → ( 𝑏 ∈ 𝑙 ↔ 𝐵 ∈ 𝑙 ) )
10 8 9 bi2anan9 ⊢ ( ( 𝑎 = 𝐴 ∧ 𝑏 = 𝐵 ) → ( ( 𝑎 ∈ 𝑙 ∧ 𝑏 ∈ 𝑙 ) ↔ ( 𝐴 ∈ 𝑙 ∧ 𝐵 ∈ 𝑙 ) ) )
11 10 reubidv ⊢ ( ( 𝑎 = 𝐴 ∧ 𝑏 = 𝐵 ) → ( ∃! 𝑙 ∈ 𝐺 ( 𝑎 ∈ 𝑙 ∧ 𝑏 ∈ 𝑙 ) ↔ ∃! 𝑙 ∈ 𝐺 ( 𝐴 ∈ 𝑙 ∧ 𝐵 ∈ 𝑙 ) ) )
12 7 11 imbi12d ⊢ ( ( 𝑎 = 𝐴 ∧ 𝑏 = 𝐵 ) → ( ( 𝑎 ≠ 𝑏 → ∃! 𝑙 ∈ 𝐺 ( 𝑎 ∈ 𝑙 ∧ 𝑏 ∈ 𝑙 ) ) ↔ ( 𝐴 ≠ 𝐵 → ∃! 𝑙 ∈ 𝐺 ( 𝐴 ∈ 𝑙 ∧ 𝐵 ∈ 𝑙 ) ) ) )
13 12 rspc2gv ⊢ ( ( 𝐴 ∈ 𝑃 ∧ 𝐵 ∈ 𝑃 ) → ( ∀ 𝑎 ∈ 𝑃 ∀ 𝑏 ∈ 𝑃 ( 𝑎 ≠ 𝑏 → ∃! 𝑙 ∈ 𝐺 ( 𝑎 ∈ 𝑙 ∧ 𝑏 ∈ 𝑙 ) ) → ( 𝐴 ≠ 𝐵 → ∃! 𝑙 ∈ 𝐺 ( 𝐴 ∈ 𝑙 ∧ 𝐵 ∈ 𝑙 ) ) ) )
14 13 com23 ⊢ ( ( 𝐴 ∈ 𝑃 ∧ 𝐵 ∈ 𝑃 ) → ( 𝐴 ≠ 𝐵 → ( ∀ 𝑎 ∈ 𝑃 ∀ 𝑏 ∈ 𝑃 ( 𝑎 ≠ 𝑏 → ∃! 𝑙 ∈ 𝐺 ( 𝑎 ∈ 𝑙 ∧ 𝑏 ∈ 𝑙 ) ) → ∃! 𝑙 ∈ 𝐺 ( 𝐴 ∈ 𝑙 ∧ 𝐵 ∈ 𝑙 ) ) ) )
15 14 imp ⊢ ( ( ( 𝐴 ∈ 𝑃 ∧ 𝐵 ∈ 𝑃 ) ∧ 𝐴 ≠ 𝐵 ) → ( ∀ 𝑎 ∈ 𝑃 ∀ 𝑏 ∈ 𝑃 ( 𝑎 ≠ 𝑏 → ∃! 𝑙 ∈ 𝐺 ( 𝑎 ∈ 𝑙 ∧ 𝑏 ∈ 𝑙 ) ) → ∃! 𝑙 ∈ 𝐺 ( 𝐴 ∈ 𝑙 ∧ 𝐵 ∈ 𝑙 ) ) )
16 15 com12 ⊢ ( ∀ 𝑎 ∈ 𝑃 ∀ 𝑏 ∈ 𝑃 ( 𝑎 ≠ 𝑏 → ∃! 𝑙 ∈ 𝐺 ( 𝑎 ∈ 𝑙 ∧ 𝑏 ∈ 𝑙 ) ) → ( ( ( 𝐴 ∈ 𝑃 ∧ 𝐵 ∈ 𝑃 ) ∧ 𝐴 ≠ 𝐵 ) → ∃! 𝑙 ∈ 𝐺 ( 𝐴 ∈ 𝑙 ∧ 𝐵 ∈ 𝑙 ) ) )
17 3 4 16 3syl ⊢ ( 𝐺 ∈ Plig → ( ( ( 𝐴 ∈ 𝑃 ∧ 𝐵 ∈ 𝑃 ) ∧ 𝐴 ≠ 𝐵 ) → ∃! 𝑙 ∈ 𝐺 ( 𝐴 ∈ 𝑙 ∧ 𝐵 ∈ 𝑙 ) ) )
18 17 imp ⊢ ( ( 𝐺 ∈ Plig ∧ ( ( 𝐴 ∈ 𝑃 ∧ 𝐵 ∈ 𝑃 ) ∧ 𝐴 ≠ 𝐵 ) ) → ∃! 𝑙 ∈ 𝐺 ( 𝐴 ∈ 𝑙 ∧ 𝐵 ∈ 𝑙 ) )