Metamath Proof Explorer


Theorem igamcl

Description: Closure of the inverse Gamma function. (Contributed by Mario Carneiro, 16-Jul-2017)

Ref Expression
Assertion igamcl ( 𝐴 ∈ ℂ → ( 1/Γ ‘ 𝐴 ) ∈ ℂ )

Proof

Step Hyp Ref Expression
1 igamval ⊢ ( 𝐴 ∈ ℂ → ( 1/Γ ‘ 𝐴 ) = if ( 𝐴 ∈ ( ℤ ∖ ℕ ) , 0 , ( 1 / ( Γ ‘ 𝐴 ) ) ) )
2 0cnd ⊢ ( ( 𝐴 ∈ ℂ ∧ 𝐴 ∈ ( ℤ ∖ ℕ ) ) → 0 ∈ ℂ )
3 eldif ⊢ ( 𝐴 ∈ ( ℂ ∖ ( ℤ ∖ ℕ ) ) ↔ ( 𝐴 ∈ ℂ ∧ ¬ 𝐴 ∈ ( ℤ ∖ ℕ ) ) )
4 gamcl ⊢ ( 𝐴 ∈ ( ℂ ∖ ( ℤ ∖ ℕ ) ) → ( Γ ‘ 𝐴 ) ∈ ℂ )
5 gamne0 ⊢ ( 𝐴 ∈ ( ℂ ∖ ( ℤ ∖ ℕ ) ) → ( Γ ‘ 𝐴 ) ≠ 0 )
6 4 5 reccld ⊢ ( 𝐴 ∈ ( ℂ ∖ ( ℤ ∖ ℕ ) ) → ( 1 / ( Γ ‘ 𝐴 ) ) ∈ ℂ )
7 3 6 sylbir ⊢ ( ( 𝐴 ∈ ℂ ∧ ¬ 𝐴 ∈ ( ℤ ∖ ℕ ) ) → ( 1 / ( Γ ‘ 𝐴 ) ) ∈ ℂ )
8 2 7 ifclda ⊢ ( 𝐴 ∈ ℂ → if ( 𝐴 ∈ ( ℤ ∖ ℕ ) , 0 , ( 1 / ( Γ ‘ 𝐴 ) ) ) ∈ ℂ )
9 1 8 eqeltrd ⊢ ( 𝐴 ∈ ℂ → ( 1/Γ ‘ 𝐴 ) ∈ ℂ )