Metamath Proof Explorer


Theorem lmhmrnlss

Description: The range of a homomorphism is a submodule. (Contributed by Stefan O'Rear, 1-Jan-2015)

Ref Expression
Assertion lmhmrnlss ( 𝐹 ∈ ( 𝑆 LMHom 𝑇 ) → ran 𝐹 ∈ ( LSubSp ‘ 𝑇 ) )

Proof

Step Hyp Ref Expression
1 eqid ( Base ‘ 𝑆 ) = ( Base ‘ 𝑆 )
2 eqid ( Base ‘ 𝑇 ) = ( Base ‘ 𝑇 )
3 1 2 lmhmf ( 𝐹 ∈ ( 𝑆 LMHom 𝑇 ) → 𝐹 : ( Base ‘ 𝑆 ) ⟶ ( Base ‘ 𝑇 ) )
4 ffn ( 𝐹 : ( Base ‘ 𝑆 ) ⟶ ( Base ‘ 𝑇 ) → 𝐹 Fn ( Base ‘ 𝑆 ) )
5 fnima ( 𝐹 Fn ( Base ‘ 𝑆 ) → ( 𝐹 “ ( Base ‘ 𝑆 ) ) = ran 𝐹 )
6 3 4 5 3syl ( 𝐹 ∈ ( 𝑆 LMHom 𝑇 ) → ( 𝐹 “ ( Base ‘ 𝑆 ) ) = ran 𝐹 )
7 lmhmlmod1 ( 𝐹 ∈ ( 𝑆 LMHom 𝑇 ) → 𝑆 ∈ LMod )
8 eqid ( LSubSp ‘ 𝑆 ) = ( LSubSp ‘ 𝑆 )
9 1 8 lss1 ( 𝑆 ∈ LMod → ( Base ‘ 𝑆 ) ∈ ( LSubSp ‘ 𝑆 ) )
10 7 9 syl ( 𝐹 ∈ ( 𝑆 LMHom 𝑇 ) → ( Base ‘ 𝑆 ) ∈ ( LSubSp ‘ 𝑆 ) )
11 eqid ( LSubSp ‘ 𝑇 ) = ( LSubSp ‘ 𝑇 )
12 8 11 lmhmima ( ( 𝐹 ∈ ( 𝑆 LMHom 𝑇 ) ∧ ( Base ‘ 𝑆 ) ∈ ( LSubSp ‘ 𝑆 ) ) → ( 𝐹 “ ( Base ‘ 𝑆 ) ) ∈ ( LSubSp ‘ 𝑇 ) )
13 10 12 mpdan ( 𝐹 ∈ ( 𝑆 LMHom 𝑇 ) → ( 𝐹 “ ( Base ‘ 𝑆 ) ) ∈ ( LSubSp ‘ 𝑇 ) )
14 6 13 eqeltrrd ( 𝐹 ∈ ( 𝑆 LMHom 𝑇 ) → ran 𝐹 ∈ ( LSubSp ‘ 𝑇 ) )