Metamath Proof Explorer


Theorem mbfmfun

Description: A measurable function is a function. (Contributed by Thierry Arnoux, 24-Jan-2017)

Ref Expression
Hypothesis mbfmfun.1 ⊢ ( 𝜑 → 𝐹 ∈ ∪ ran MblFnM )
Assertion mbfmfun ( 𝜑 → Fun 𝐹 )

Proof

Step Hyp Ref Expression
1 mbfmfun.1 ⊢ ( 𝜑 → 𝐹 ∈ ∪ ran MblFnM )
2 elunirnmbfm ⊢ ( 𝐹 ∈ ∪ ran MblFnM ↔ ∃ 𝑠 ∈ ∪ ran sigAlgebra ∃ 𝑡 ∈ ∪ ran sigAlgebra ( 𝐹 ∈ ( ∪ 𝑡 ↑m ∪ 𝑠 ) ∧ ∀ 𝑥 ∈ 𝑡 ( ◡ 𝐹 “ 𝑥 ) ∈ 𝑠 ) )
3 2 biimpi ⊢ ( 𝐹 ∈ ∪ ran MblFnM → ∃ 𝑠 ∈ ∪ ran sigAlgebra ∃ 𝑡 ∈ ∪ ran sigAlgebra ( 𝐹 ∈ ( ∪ 𝑡 ↑m ∪ 𝑠 ) ∧ ∀ 𝑥 ∈ 𝑡 ( ◡ 𝐹 “ 𝑥 ) ∈ 𝑠 ) )
4 elmapfun ⊢ ( 𝐹 ∈ ( ∪ 𝑡 ↑m ∪ 𝑠 ) → Fun 𝐹 )
5 4 adantr ⊢ ( ( 𝐹 ∈ ( ∪ 𝑡 ↑m ∪ 𝑠 ) ∧ ∀ 𝑥 ∈ 𝑡 ( ◡ 𝐹 “ 𝑥 ) ∈ 𝑠 ) → Fun 𝐹 )
6 5 rexlimivw ⊢ ( ∃ 𝑡 ∈ ∪ ran sigAlgebra ( 𝐹 ∈ ( ∪ 𝑡 ↑m ∪ 𝑠 ) ∧ ∀ 𝑥 ∈ 𝑡 ( ◡ 𝐹 “ 𝑥 ) ∈ 𝑠 ) → Fun 𝐹 )
7 6 rexlimivw ⊢ ( ∃ 𝑠 ∈ ∪ ran sigAlgebra ∃ 𝑡 ∈ ∪ ran sigAlgebra ( 𝐹 ∈ ( ∪ 𝑡 ↑m ∪ 𝑠 ) ∧ ∀ 𝑥 ∈ 𝑡 ( ◡ 𝐹 “ 𝑥 ) ∈ 𝑠 ) → Fun 𝐹 )
8 1 3 7 3syl ⊢ ( 𝜑 → Fun 𝐹 )