Metamath Proof Explorer


Theorem srg1zr

Description: The only semiring with a base set consisting of one element is the zero ring (at least if its operations are internal binary operations). (Contributed by FL, 13-Feb-2010) (Revised by AV, 25-Jan-2020) (Proof shortened by AV, 19-Jun-2026)

Ref Expression
Hypotheses srg1zr.b 𝐵 = ( Base ‘ 𝑅 )
srg1zr.p + = ( +g𝑅 )
srg1zr.t = ( .r𝑅 )
Assertion srg1zr ( ( ( 𝑅 ∈ SRing ∧ + Fn ( 𝐵 × 𝐵 ) ∧ Fn ( 𝐵 × 𝐵 ) ) ∧ 𝑍𝐵 ) → ( 𝐵 = { 𝑍 } ↔ ( + = { ⟨ ⟨ 𝑍 , 𝑍 ⟩ , 𝑍 ⟩ } ∧ = { ⟨ ⟨ 𝑍 , 𝑍 ⟩ , 𝑍 ⟩ } ) ) )

Proof

Step Hyp Ref Expression
1 srg1zr.b 𝐵 = ( Base ‘ 𝑅 )
2 srg1zr.p + = ( +g𝑅 )
3 srg1zr.t = ( .r𝑅 )
4 srgmnd ( 𝑅 ∈ SRing → 𝑅 ∈ Mnd )
5 mndmgm ( 𝑅 ∈ Mnd → 𝑅 ∈ Mgm )
6 4 5 syl ( 𝑅 ∈ SRing → 𝑅 ∈ Mgm )
7 eqid ( mulGrp ‘ 𝑅 ) = ( mulGrp ‘ 𝑅 )
8 7 srgmgp ( 𝑅 ∈ SRing → ( mulGrp ‘ 𝑅 ) ∈ Mnd )
9 mndmgm ( ( mulGrp ‘ 𝑅 ) ∈ Mnd → ( mulGrp ‘ 𝑅 ) ∈ Mgm )
10 8 9 syl ( 𝑅 ∈ SRing → ( mulGrp ‘ 𝑅 ) ∈ Mgm )
11 6 10 jca ( 𝑅 ∈ SRing → ( 𝑅 ∈ Mgm ∧ ( mulGrp ‘ 𝑅 ) ∈ Mgm ) )
12 11 3ad2ant1 ( ( 𝑅 ∈ SRing ∧ + Fn ( 𝐵 × 𝐵 ) ∧ Fn ( 𝐵 × 𝐵 ) ) → ( 𝑅 ∈ Mgm ∧ ( mulGrp ‘ 𝑅 ) ∈ Mgm ) )
13 12 adantr ( ( ( 𝑅 ∈ SRing ∧ + Fn ( 𝐵 × 𝐵 ) ∧ Fn ( 𝐵 × 𝐵 ) ) ∧ 𝑍𝐵 ) → ( 𝑅 ∈ Mgm ∧ ( mulGrp ‘ 𝑅 ) ∈ Mgm ) )
14 3simpc ( ( 𝑅 ∈ SRing ∧ + Fn ( 𝐵 × 𝐵 ) ∧ Fn ( 𝐵 × 𝐵 ) ) → ( + Fn ( 𝐵 × 𝐵 ) ∧ Fn ( 𝐵 × 𝐵 ) ) )
15 14 adantr ( ( ( 𝑅 ∈ SRing ∧ + Fn ( 𝐵 × 𝐵 ) ∧ Fn ( 𝐵 × 𝐵 ) ) ∧ 𝑍𝐵 ) → ( + Fn ( 𝐵 × 𝐵 ) ∧ Fn ( 𝐵 × 𝐵 ) ) )
16 simpr ( ( ( 𝑅 ∈ SRing ∧ + Fn ( 𝐵 × 𝐵 ) ∧ Fn ( 𝐵 × 𝐵 ) ) ∧ 𝑍𝐵 ) → 𝑍𝐵 )
17 1 2 3 rng1zrlem ( ( ( 𝑅 ∈ Mgm ∧ ( mulGrp ‘ 𝑅 ) ∈ Mgm ) ∧ ( + Fn ( 𝐵 × 𝐵 ) ∧ Fn ( 𝐵 × 𝐵 ) ) ∧ 𝑍𝐵 ) → ( 𝐵 = { 𝑍 } ↔ ( + = { ⟨ ⟨ 𝑍 , 𝑍 ⟩ , 𝑍 ⟩ } ∧ = { ⟨ ⟨ 𝑍 , 𝑍 ⟩ , 𝑍 ⟩ } ) ) )
18 13 15 16 17 syl3anc ( ( ( 𝑅 ∈ SRing ∧ + Fn ( 𝐵 × 𝐵 ) ∧ Fn ( 𝐵 × 𝐵 ) ) ∧ 𝑍𝐵 ) → ( 𝐵 = { 𝑍 } ↔ ( + = { ⟨ ⟨ 𝑍 , 𝑍 ⟩ , 𝑍 ⟩ } ∧ = { ⟨ ⟨ 𝑍 , 𝑍 ⟩ , 𝑍 ⟩ } ) ) )