Metamath Proof Explorer


Theorem sseqfres

Description: The first elements in the strong recursive sequence are the sequence initializer. (Contributed by Thierry Arnoux, 23-Apr-2019)

Ref Expression
Hypotheses sseqval.1 ⊢ ( 𝜑 → 𝑆 ∈ V )
sseqval.2 ⊢ ( 𝜑 → 𝑀 ∈ Word 𝑆 )
sseqval.3 ⊢ 𝑊 = ( Word 𝑆 ∩ ( ◡ ♯ “ ( ℤ≥ ‘ ( ♯ ‘ 𝑀 ) ) ) )
sseqval.4 ⊢ ( 𝜑 → 𝐹 : 𝑊 ⟶ 𝑆 )
Assertion sseqfres ( 𝜑 → ( ( 𝑀 seqstr 𝐹 ) ↾ ( 0 ..^ ( ♯ ‘ 𝑀 ) ) ) = 𝑀 )

Proof

Step Hyp Ref Expression
1 sseqval.1 ⊢ ( 𝜑 → 𝑆 ∈ V )
2 sseqval.2 ⊢ ( 𝜑 → 𝑀 ∈ Word 𝑆 )
3 sseqval.3 ⊢ 𝑊 = ( Word 𝑆 ∩ ( ◡ ♯ “ ( ℤ≥ ‘ ( ♯ ‘ 𝑀 ) ) ) )
4 sseqval.4 ⊢ ( 𝜑 → 𝐹 : 𝑊 ⟶ 𝑆 )
5 1 adantr ⊢ ( ( 𝜑 ∧ 𝑖 ∈ ( 0 ..^ ( ♯ ‘ 𝑀 ) ) ) → 𝑆 ∈ V )
6 2 adantr ⊢ ( ( 𝜑 ∧ 𝑖 ∈ ( 0 ..^ ( ♯ ‘ 𝑀 ) ) ) → 𝑀 ∈ Word 𝑆 )
7 4 adantr ⊢ ( ( 𝜑 ∧ 𝑖 ∈ ( 0 ..^ ( ♯ ‘ 𝑀 ) ) ) → 𝐹 : 𝑊 ⟶ 𝑆 )
8 simpr ⊢ ( ( 𝜑 ∧ 𝑖 ∈ ( 0 ..^ ( ♯ ‘ 𝑀 ) ) ) → 𝑖 ∈ ( 0 ..^ ( ♯ ‘ 𝑀 ) ) )
9 5 6 3 7 8 sseqfv1 ⊢ ( ( 𝜑 ∧ 𝑖 ∈ ( 0 ..^ ( ♯ ‘ 𝑀 ) ) ) → ( ( 𝑀 seqstr 𝐹 ) ‘ 𝑖 ) = ( 𝑀 ‘ 𝑖 ) )
10 9 ralrimiva ⊢ ( 𝜑 → ∀ 𝑖 ∈ ( 0 ..^ ( ♯ ‘ 𝑀 ) ) ( ( 𝑀 seqstr 𝐹 ) ‘ 𝑖 ) = ( 𝑀 ‘ 𝑖 ) )
11 1 2 3 4 sseqfn ⊢ ( 𝜑 → ( 𝑀 seqstr 𝐹 ) Fn ℕ0 )
12 wrdfn ⊢ ( 𝑀 ∈ Word 𝑆 → 𝑀 Fn ( 0 ..^ ( ♯ ‘ 𝑀 ) ) )
13 2 12 syl ⊢ ( 𝜑 → 𝑀 Fn ( 0 ..^ ( ♯ ‘ 𝑀 ) ) )
14 fzo0ssnn0 ⊢ ( 0 ..^ ( ♯ ‘ 𝑀 ) ) ⊆ ℕ0
15 14 a1i ⊢ ( 𝜑 → ( 0 ..^ ( ♯ ‘ 𝑀 ) ) ⊆ ℕ0 )
16 fvreseq1 ⊢ ( ( ( ( 𝑀 seqstr 𝐹 ) Fn ℕ0 ∧ 𝑀 Fn ( 0 ..^ ( ♯ ‘ 𝑀 ) ) ) ∧ ( 0 ..^ ( ♯ ‘ 𝑀 ) ) ⊆ ℕ0 ) → ( ( ( 𝑀 seqstr 𝐹 ) ↾ ( 0 ..^ ( ♯ ‘ 𝑀 ) ) ) = 𝑀 ↔ ∀ 𝑖 ∈ ( 0 ..^ ( ♯ ‘ 𝑀 ) ) ( ( 𝑀 seqstr 𝐹 ) ‘ 𝑖 ) = ( 𝑀 ‘ 𝑖 ) ) )
17 11 13 15 16 syl21anc ⊢ ( 𝜑 → ( ( ( 𝑀 seqstr 𝐹 ) ↾ ( 0 ..^ ( ♯ ‘ 𝑀 ) ) ) = 𝑀 ↔ ∀ 𝑖 ∈ ( 0 ..^ ( ♯ ‘ 𝑀 ) ) ( ( 𝑀 seqstr 𝐹 ) ‘ 𝑖 ) = ( 𝑀 ‘ 𝑖 ) ) )
18 10 17 mpbird ⊢ ( 𝜑 → ( ( 𝑀 seqstr 𝐹 ) ↾ ( 0 ..^ ( ♯ ‘ 𝑀 ) ) ) = 𝑀 )