Metamath Proof Explorer


Theorem tanhneg

Description: The tanh function is odd. (Contributed by Jon Pennant, 22-Oct-2026)

Ref Expression
Assertion tanhneg ( ( 𝐴 ∈ ℂ ∧ ( cosh ‘ 𝐴 ) ≠ 0 ) → ( tanh ‘ - 𝐴 ) = - ( tanh ‘ 𝐴 ) )

Proof

Step Hyp Ref Expression
1 sinhcl ⊢ ( 𝐴 ∈ ℂ → ( sinh ‘ 𝐴 ) ∈ ℂ )
2 1 adantr ⊢ ( ( 𝐴 ∈ ℂ ∧ ( cosh ‘ 𝐴 ) ≠ 0 ) → ( sinh ‘ 𝐴 ) ∈ ℂ )
3 coshcl ⊢ ( 𝐴 ∈ ℂ → ( cosh ‘ 𝐴 ) ∈ ℂ )
4 3 adantr ⊢ ( ( 𝐴 ∈ ℂ ∧ ( cosh ‘ 𝐴 ) ≠ 0 ) → ( cosh ‘ 𝐴 ) ∈ ℂ )
5 simpr ⊢ ( ( 𝐴 ∈ ℂ ∧ ( cosh ‘ 𝐴 ) ≠ 0 ) → ( cosh ‘ 𝐴 ) ≠ 0 )
6 2 4 5 divnegd ⊢ ( ( 𝐴 ∈ ℂ ∧ ( cosh ‘ 𝐴 ) ≠ 0 ) → - ( ( sinh ‘ 𝐴 ) / ( cosh ‘ 𝐴 ) ) = ( - ( sinh ‘ 𝐴 ) / ( cosh ‘ 𝐴 ) ) )
7 tanhval ⊢ ( ( 𝐴 ∈ ℂ ∧ ( cosh ‘ 𝐴 ) ≠ 0 ) → ( tanh ‘ 𝐴 ) = ( ( sinh ‘ 𝐴 ) / ( cosh ‘ 𝐴 ) ) )
8 7 negeqd ⊢ ( ( 𝐴 ∈ ℂ ∧ ( cosh ‘ 𝐴 ) ≠ 0 ) → - ( tanh ‘ 𝐴 ) = - ( ( sinh ‘ 𝐴 ) / ( cosh ‘ 𝐴 ) ) )
9 negcl ⊢ ( 𝐴 ∈ ℂ → - 𝐴 ∈ ℂ )
10 coshneg ⊢ ( 𝐴 ∈ ℂ → ( cosh ‘ - 𝐴 ) = ( cosh ‘ 𝐴 ) )
11 10 adantr ⊢ ( ( 𝐴 ∈ ℂ ∧ ( cosh ‘ 𝐴 ) ≠ 0 ) → ( cosh ‘ - 𝐴 ) = ( cosh ‘ 𝐴 ) )
12 11 5 eqnetrd ⊢ ( ( 𝐴 ∈ ℂ ∧ ( cosh ‘ 𝐴 ) ≠ 0 ) → ( cosh ‘ - 𝐴 ) ≠ 0 )
13 tanhval ⊢ ( ( - 𝐴 ∈ ℂ ∧ ( cosh ‘ - 𝐴 ) ≠ 0 ) → ( tanh ‘ - 𝐴 ) = ( ( sinh ‘ - 𝐴 ) / ( cosh ‘ - 𝐴 ) ) )
14 9 12 13 syl2an2r ⊢ ( ( 𝐴 ∈ ℂ ∧ ( cosh ‘ 𝐴 ) ≠ 0 ) → ( tanh ‘ - 𝐴 ) = ( ( sinh ‘ - 𝐴 ) / ( cosh ‘ - 𝐴 ) ) )
15 sinhneg ⊢ ( 𝐴 ∈ ℂ → ( sinh ‘ - 𝐴 ) = - ( sinh ‘ 𝐴 ) )
16 15 adantr ⊢ ( ( 𝐴 ∈ ℂ ∧ ( cosh ‘ 𝐴 ) ≠ 0 ) → ( sinh ‘ - 𝐴 ) = - ( sinh ‘ 𝐴 ) )
17 16 11 oveq12d ⊢ ( ( 𝐴 ∈ ℂ ∧ ( cosh ‘ 𝐴 ) ≠ 0 ) → ( ( sinh ‘ - 𝐴 ) / ( cosh ‘ - 𝐴 ) ) = ( - ( sinh ‘ 𝐴 ) / ( cosh ‘ 𝐴 ) ) )
18 14 17 eqtrd ⊢ ( ( 𝐴 ∈ ℂ ∧ ( cosh ‘ 𝐴 ) ≠ 0 ) → ( tanh ‘ - 𝐴 ) = ( - ( sinh ‘ 𝐴 ) / ( cosh ‘ 𝐴 ) ) )
19 6 8 18 3eqtr4rd ⊢ ( ( 𝐴 ∈ ℂ ∧ ( cosh ‘ 𝐴 ) ≠ 0 ) → ( tanh ‘ - 𝐴 ) = - ( tanh ‘ 𝐴 ) )