Metamath Proof Explorer


Theorem tanhneg

Description: The tanh function is odd. (Contributed by Jon Pennant, 22-Oct-2026)

Ref Expression
Assertion tanhneg ⊢ A ∈ ℂ ∧ cosh ⁡ A ≠ 0 → tanh ⁡ − A = − tanh ⁡ A

Proof

Step Hyp Ref Expression
1 sinhcl ⊢ A ∈ ℂ → sinh ⁡ A ∈ ℂ
2 1 adantr ⊢ A ∈ ℂ ∧ cosh ⁡ A ≠ 0 → sinh ⁡ A ∈ ℂ
3 coshcl ⊢ A ∈ ℂ → cosh ⁡ A ∈ ℂ
4 3 adantr ⊢ A ∈ ℂ ∧ cosh ⁡ A ≠ 0 → cosh ⁡ A ∈ ℂ
5 simpr ⊢ A ∈ ℂ ∧ cosh ⁡ A ≠ 0 → cosh ⁡ A ≠ 0
6 2 4 5 divnegd ⊢ A ∈ ℂ ∧ cosh ⁡ A ≠ 0 → − sinh ⁡ A cosh ⁡ A = − sinh ⁡ A cosh ⁡ A
7 tanhval ⊢ A ∈ ℂ ∧ cosh ⁡ A ≠ 0 → tanh ⁡ A = sinh ⁡ A cosh ⁡ A
8 7 negeqd ⊢ A ∈ ℂ ∧ cosh ⁡ A ≠ 0 → − tanh ⁡ A = − sinh ⁡ A cosh ⁡ A
9 negcl ⊢ A ∈ ℂ → − A ∈ ℂ
10 coshneg ⊢ A ∈ ℂ → cosh ⁡ − A = cosh ⁡ A
11 10 adantr ⊢ A ∈ ℂ ∧ cosh ⁡ A ≠ 0 → cosh ⁡ − A = cosh ⁡ A
12 11 5 eqnetrd ⊢ A ∈ ℂ ∧ cosh ⁡ A ≠ 0 → cosh ⁡ − A ≠ 0
13 tanhval ⊢ − A ∈ ℂ ∧ cosh ⁡ − A ≠ 0 → tanh ⁡ − A = sinh ⁡ − A cosh ⁡ − A
14 9 12 13 syl2an2r ⊢ A ∈ ℂ ∧ cosh ⁡ A ≠ 0 → tanh ⁡ − A = sinh ⁡ − A cosh ⁡ − A
15 sinhneg ⊢ A ∈ ℂ → sinh ⁡ − A = − sinh ⁡ A
16 15 adantr ⊢ A ∈ ℂ ∧ cosh ⁡ A ≠ 0 → sinh ⁡ − A = − sinh ⁡ A
17 16 11 oveq12d ⊢ A ∈ ℂ ∧ cosh ⁡ A ≠ 0 → sinh ⁡ − A cosh ⁡ − A = − sinh ⁡ A cosh ⁡ A
18 14 17 eqtrd ⊢ A ∈ ℂ ∧ cosh ⁡ A ≠ 0 → tanh ⁡ − A = − sinh ⁡ A cosh ⁡ A
19 6 8 18 3eqtr4rd ⊢ A ∈ ℂ ∧ cosh ⁡ A ≠ 0 → tanh ⁡ − A = − tanh ⁡ A