Metamath Proof Explorer


Theorem tfsconcat00

Description: The concatentation of two empty series results in an empty series. (Contributed by RP, 25-Feb-2025)

Ref Expression
Hypothesis tfsconcat.op ⊢ + = ( 𝑎 ∈ V , 𝑏 ∈ V ↦ ( 𝑎 ∪ { ⟨ 𝑥 , 𝑦 ⟩ ∣ ( 𝑥 ∈ ( ( dom 𝑎 +o dom 𝑏 ) ∖ dom 𝑎 ) ∧ ∃ 𝑧 ∈ dom 𝑏 ( 𝑥 = ( dom 𝑎 +o 𝑧 ) ∧ 𝑦 = ( 𝑏 ‘ 𝑧 ) ) ) } ) )
Assertion tfsconcat00 ( ( ( 𝐴 Fn 𝐶 ∧ 𝐵 Fn 𝐷 ) ∧ ( 𝐶 ∈ On ∧ 𝐷 ∈ On ) ) → ( ( 𝐴 = ∅ ∧ 𝐵 = ∅ ) ↔ ( 𝐴 + 𝐵 ) = ∅ ) )

Proof

Step Hyp Ref Expression
1 tfsconcat.op ⊢ + = ( 𝑎 ∈ V , 𝑏 ∈ V ↦ ( 𝑎 ∪ { ⟨ 𝑥 , 𝑦 ⟩ ∣ ( 𝑥 ∈ ( ( dom 𝑎 +o dom 𝑏 ) ∖ dom 𝑎 ) ∧ ∃ 𝑧 ∈ dom 𝑏 ( 𝑥 = ( dom 𝑎 +o 𝑧 ) ∧ 𝑦 = ( 𝑏 ‘ 𝑧 ) ) ) } ) )
2 1 tfsconcatrn ⊢ ( ( ( 𝐴 Fn 𝐶 ∧ 𝐵 Fn 𝐷 ) ∧ ( 𝐶 ∈ On ∧ 𝐷 ∈ On ) ) → ran ( 𝐴 + 𝐵 ) = ( ran 𝐴 ∪ ran 𝐵 ) )
3 2 eqeq1d ⊢ ( ( ( 𝐴 Fn 𝐶 ∧ 𝐵 Fn 𝐷 ) ∧ ( 𝐶 ∈ On ∧ 𝐷 ∈ On ) ) → ( ran ( 𝐴 + 𝐵 ) = ∅ ↔ ( ran 𝐴 ∪ ran 𝐵 ) = ∅ ) )
4 1 tfsconcatfn ⊢ ( ( ( 𝐴 Fn 𝐶 ∧ 𝐵 Fn 𝐷 ) ∧ ( 𝐶 ∈ On ∧ 𝐷 ∈ On ) ) → ( 𝐴 + 𝐵 ) Fn ( 𝐶 +o 𝐷 ) )
5 fnrel ⊢ ( ( 𝐴 + 𝐵 ) Fn ( 𝐶 +o 𝐷 ) → Rel ( 𝐴 + 𝐵 ) )
6 relrn0 ⊢ ( Rel ( 𝐴 + 𝐵 ) → ( ( 𝐴 + 𝐵 ) = ∅ ↔ ran ( 𝐴 + 𝐵 ) = ∅ ) )
7 4 5 6 3syl ⊢ ( ( ( 𝐴 Fn 𝐶 ∧ 𝐵 Fn 𝐷 ) ∧ ( 𝐶 ∈ On ∧ 𝐷 ∈ On ) ) → ( ( 𝐴 + 𝐵 ) = ∅ ↔ ran ( 𝐴 + 𝐵 ) = ∅ ) )
8 fnrel ⊢ ( 𝐴 Fn 𝐶 → Rel 𝐴 )
9 relrn0 ⊢ ( Rel 𝐴 → ( 𝐴 = ∅ ↔ ran 𝐴 = ∅ ) )
10 8 9 syl ⊢ ( 𝐴 Fn 𝐶 → ( 𝐴 = ∅ ↔ ran 𝐴 = ∅ ) )
11 fnrel ⊢ ( 𝐵 Fn 𝐷 → Rel 𝐵 )
12 relrn0 ⊢ ( Rel 𝐵 → ( 𝐵 = ∅ ↔ ran 𝐵 = ∅ ) )
13 11 12 syl ⊢ ( 𝐵 Fn 𝐷 → ( 𝐵 = ∅ ↔ ran 𝐵 = ∅ ) )
14 10 13 bi2anan9 ⊢ ( ( 𝐴 Fn 𝐶 ∧ 𝐵 Fn 𝐷 ) → ( ( 𝐴 = ∅ ∧ 𝐵 = ∅ ) ↔ ( ran 𝐴 = ∅ ∧ ran 𝐵 = ∅ ) ) )
15 un00 ⊢ ( ( ran 𝐴 = ∅ ∧ ran 𝐵 = ∅ ) ↔ ( ran 𝐴 ∪ ran 𝐵 ) = ∅ )
16 14 15 bitrdi ⊢ ( ( 𝐴 Fn 𝐶 ∧ 𝐵 Fn 𝐷 ) → ( ( 𝐴 = ∅ ∧ 𝐵 = ∅ ) ↔ ( ran 𝐴 ∪ ran 𝐵 ) = ∅ ) )
17 16 adantr ⊢ ( ( ( 𝐴 Fn 𝐶 ∧ 𝐵 Fn 𝐷 ) ∧ ( 𝐶 ∈ On ∧ 𝐷 ∈ On ) ) → ( ( 𝐴 = ∅ ∧ 𝐵 = ∅ ) ↔ ( ran 𝐴 ∪ ran 𝐵 ) = ∅ ) )
18 3 7 17 3bitr4rd ⊢ ( ( ( 𝐴 Fn 𝐶 ∧ 𝐵 Fn 𝐷 ) ∧ ( 𝐶 ∈ On ∧ 𝐷 ∈ On ) ) → ( ( 𝐴 = ∅ ∧ 𝐵 = ∅ ) ↔ ( 𝐴 + 𝐵 ) = ∅ ) )