Metamath Proof Explorer


Theorem unelsiga

Description: A sigma-algebra is closed under pairwise unions. (Contributed by Thierry Arnoux, 13-Dec-2016)

Ref Expression
Assertion unelsiga ( ( 𝑆 ∈ ∪ ran sigAlgebra ∧ 𝐴 ∈ 𝑆 ∧ 𝐵 ∈ 𝑆 ) → ( 𝐴 ∪ 𝐵 ) ∈ 𝑆 )

Proof

Step Hyp Ref Expression
1 uniprg ⊢ ( ( 𝐴 ∈ 𝑆 ∧ 𝐵 ∈ 𝑆 ) → ∪ { 𝐴 , 𝐵 } = ( 𝐴 ∪ 𝐵 ) )
2 1 3adant1 ⊢ ( ( 𝑆 ∈ ∪ ran sigAlgebra ∧ 𝐴 ∈ 𝑆 ∧ 𝐵 ∈ 𝑆 ) → ∪ { 𝐴 , 𝐵 } = ( 𝐴 ∪ 𝐵 ) )
3 isrnsigau ⊢ ( 𝑆 ∈ ∪ ran sigAlgebra → ( 𝑆 ⊆ 𝒫 ∪ 𝑆 ∧ ( ∪ 𝑆 ∈ 𝑆 ∧ ∀ 𝑥 ∈ 𝑆 ( ∪ 𝑆 ∖ 𝑥 ) ∈ 𝑆 ∧ ∀ 𝑥 ∈ 𝒫 𝑆 ( 𝑥 ≼ ω → ∪ 𝑥 ∈ 𝑆 ) ) ) )
4 3 simprd ⊢ ( 𝑆 ∈ ∪ ran sigAlgebra → ( ∪ 𝑆 ∈ 𝑆 ∧ ∀ 𝑥 ∈ 𝑆 ( ∪ 𝑆 ∖ 𝑥 ) ∈ 𝑆 ∧ ∀ 𝑥 ∈ 𝒫 𝑆 ( 𝑥 ≼ ω → ∪ 𝑥 ∈ 𝑆 ) ) )
5 4 simp3d ⊢ ( 𝑆 ∈ ∪ ran sigAlgebra → ∀ 𝑥 ∈ 𝒫 𝑆 ( 𝑥 ≼ ω → ∪ 𝑥 ∈ 𝑆 ) )
6 5 3ad2ant1 ⊢ ( ( 𝑆 ∈ ∪ ran sigAlgebra ∧ 𝐴 ∈ 𝑆 ∧ 𝐵 ∈ 𝑆 ) → ∀ 𝑥 ∈ 𝒫 𝑆 ( 𝑥 ≼ ω → ∪ 𝑥 ∈ 𝑆 ) )
7 prct ⊢ ( ( 𝐴 ∈ 𝑆 ∧ 𝐵 ∈ 𝑆 ) → { 𝐴 , 𝐵 } ≼ ω )
8 7 3adant1 ⊢ ( ( 𝑆 ∈ ∪ ran sigAlgebra ∧ 𝐴 ∈ 𝑆 ∧ 𝐵 ∈ 𝑆 ) → { 𝐴 , 𝐵 } ≼ ω )
9 prelpwi ⊢ ( ( 𝐴 ∈ 𝑆 ∧ 𝐵 ∈ 𝑆 ) → { 𝐴 , 𝐵 } ∈ 𝒫 𝑆 )
10 breq1 ⊢ ( 𝑥 = { 𝐴 , 𝐵 } → ( 𝑥 ≼ ω ↔ { 𝐴 , 𝐵 } ≼ ω ) )
11 unieq ⊢ ( 𝑥 = { 𝐴 , 𝐵 } → ∪ 𝑥 = ∪ { 𝐴 , 𝐵 } )
12 11 eleq1d ⊢ ( 𝑥 = { 𝐴 , 𝐵 } → ( ∪ 𝑥 ∈ 𝑆 ↔ ∪ { 𝐴 , 𝐵 } ∈ 𝑆 ) )
13 10 12 imbi12d ⊢ ( 𝑥 = { 𝐴 , 𝐵 } → ( ( 𝑥 ≼ ω → ∪ 𝑥 ∈ 𝑆 ) ↔ ( { 𝐴 , 𝐵 } ≼ ω → ∪ { 𝐴 , 𝐵 } ∈ 𝑆 ) ) )
14 13 rspcv ⊢ ( { 𝐴 , 𝐵 } ∈ 𝒫 𝑆 → ( ∀ 𝑥 ∈ 𝒫 𝑆 ( 𝑥 ≼ ω → ∪ 𝑥 ∈ 𝑆 ) → ( { 𝐴 , 𝐵 } ≼ ω → ∪ { 𝐴 , 𝐵 } ∈ 𝑆 ) ) )
15 9 14 syl ⊢ ( ( 𝐴 ∈ 𝑆 ∧ 𝐵 ∈ 𝑆 ) → ( ∀ 𝑥 ∈ 𝒫 𝑆 ( 𝑥 ≼ ω → ∪ 𝑥 ∈ 𝑆 ) → ( { 𝐴 , 𝐵 } ≼ ω → ∪ { 𝐴 , 𝐵 } ∈ 𝑆 ) ) )
16 15 3adant1 ⊢ ( ( 𝑆 ∈ ∪ ran sigAlgebra ∧ 𝐴 ∈ 𝑆 ∧ 𝐵 ∈ 𝑆 ) → ( ∀ 𝑥 ∈ 𝒫 𝑆 ( 𝑥 ≼ ω → ∪ 𝑥 ∈ 𝑆 ) → ( { 𝐴 , 𝐵 } ≼ ω → ∪ { 𝐴 , 𝐵 } ∈ 𝑆 ) ) )
17 6 8 16 mp2d ⊢ ( ( 𝑆 ∈ ∪ ran sigAlgebra ∧ 𝐴 ∈ 𝑆 ∧ 𝐵 ∈ 𝑆 ) → ∪ { 𝐴 , 𝐵 } ∈ 𝑆 )
18 2 17 eqeltrrd ⊢ ( ( 𝑆 ∈ ∪ ran sigAlgebra ∧ 𝐴 ∈ 𝑆 ∧ 𝐵 ∈ 𝑆 ) → ( 𝐴 ∪ 𝐵 ) ∈ 𝑆 )